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expeople1 [14]
3 years ago
6

Write the equilibrium constant expression for this reaction: NH(aq)—>NH3(aq)+H+ (aq)

Chemistry
1 answer:
kicyunya [14]3 years ago
5 0

Answer:

k = \frac{[NH_3][H^+]}{[NH_4^+]}

Explanation:

The equilibrium constant of a reaction is defined as the ratio of the concentrations of products over concentrations of reactants powered to its coefficients. For the reaction:

aA + bB ⇄ cC + dD

The equilibrium constant, k, is written as:

k = \frac{[C]^c[D]^d}{[A]^a[B]^b}

For the reaction:

NH₄⁺(aq) ⇄ NH₃(aq) + H⁺(aq)

The equilibrium constant is:

k = \frac{[NH_3][H^+]}{[NH_4^+]}

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<h3> What is unit cell ?</h3>

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\rm \rho =\dfrac{nM}{N_{0} a^{3}} \\\\\\\\\rm n =\dfrac{\rho N_{0} a^{3}}{M} \\\\\\\\Assuming\; it \; to \; be \; a\; BCC\; structure \\\\\\ r = \dfrac{\sqrt{3} \times a}{4} \\\\\\Therefore\; a = 3.23 \times 10^{-8}\\\\\\\\\rm n =\dfrac{13.3 \times 6.022 \times 10^{23}\times 3.23^{3}\times (10^{-8})^{3}}{135} \\\\

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To know more about unit cell

brainly.com/question/13110055

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