Atomic mass Ca = 40 a.m.u
1 mole Ca ----------- 40 g
2.5 mols Ca -------- ( mass Ca )
Mass Ca = 2.5 x 40 / 1
Mass Ca = 100 / 1
= 100 g of Ca
hope this helps!
To calculate the number of atoms of Cr, we first find the number of moles per unit of cubic centimeter of Cr. Then, use avogadros number for the number of atoms. Calculations are as follows:
1 cm^3 (7.15 g/cm^3) (1 mol / 51.996 g Cr) = 0.14 mol Cr
0.14 mol Cr ( 6.022 x 10^23 atoms Cr / 1 mol Cr ) = 8.28 x 10^22 atoms Cr
Answer:
<u>a nonspontanenous reaction is forced to occur</u>
<em>Hope</em><em> this</em><em> helps</em><em> </em><em>:</em><em>)</em>
Explanation:
The given data is as follows.
Flow of chlorine (Q) = 
Amount of liter present per day is as follows.

It is given that dosage of chlorine will be as follows.
10 mg/l =
kg/l
Therefore, total chlorine requirement is as follows.
Total chlorine requirement =
kg/day
= 100 kg/day
Thus, we can conclude that the kilograms of chlorine used daily at the given water treatment plant is 100 kg/day.