Choose all the answers that apply.

Is dimethyl amine and triethylamine more soluble in water?

kompoz [17]

No, dimethyl amine and triethyl amine are not more soluble in water. Both are soluble in water but not more soluble in water. These are also soluble in alcohol.
Dimethyl amine is a secondary amine while triethyl amine is a tertiary amine. Generally, the small amines are more soluble in water. As the hydrocarbon chain goes on increasing, the solubility goes on decreasing.

4 0

3 years ago

some places such as caves and sinkholes have lower elevations than surrounding areas infer how a sink might be shown on a topogr

Andreyy89

Answer:

By closed contours with hachures

Explanation:

A sinkhole is a depression in the ground that forms when water erodes an underlying rock layer.

Sinkholes are denoted by closed contours with tick marks (hachures) that point towards lower ground.

The topographical map below shows the difference between the contours of a hill and those of a sinkhole.

5 0

3 years ago

What is the cause of change over time in a population?

Y_Kistochka [10]

The environment modifies.

Explanation:

A modification of the environment can lead to population changes overtime. The environment is very important for population dynamics.

It is predominantly made up of the factors that affects organisms and where they live.

If the resources in an environment gets depleted, organisms will be force to migrate from that place to another in search of more nutrient areas.

This and many other factor like climate, stability, etc causes changes to the population through time.

learn more:

Population brainly.com/question/6233803

#learnwithBrainly

3 0

3 years ago

Calculate the value of ΔG°, ΔH°, & ΔS° for the oxidation of solid elemental sulfur to gaseous sulfur trioxide at at 25°C.2S

Liula [17]

Answer:

ΔG° = -750324.96 J/mol = -750.324 Kj/mol

ΔH° = - 790.4 kJ/mol = -790400 j/mol

ΔS° = = - 134.48 J K-1mol-1

Explanation:

(S, rhombic) + 3O2( g) → 2SO3 (g)

Temperature = 25°C + 273 = 298K (Converting to kelvin temperature.)

The formulae relating all four paramenters (ΔG°, T, ΔH°, & ΔS°) is given as;

ΔG° = ΔH° - TΔS°

All H and S values used are measurements at 25°C

Calculating ΔH

You started with 1 mole of Sulphur and 3 moles of oxygen.

Total starting enthalpy = 0+ 3(0) = 0 kJ/mol

You ended up with 2 moles of SO3.

Total enthalpy at the end = 2(-395.2) = - 790.4 kJ/mol

enthalpy change = what you end up with - what you started with.

ΔH = enthalpy change = - 790.4 kJ/mol - 0 kJ/mol = - 790.4 kJ/mol = -790400 j/mol

Calculating ΔS

You started with 1 mole of Sulphur and 3 moles of oxygen.

Total starting entropy =31.88 + 3(205) = 646.88 J K-1mol-1

You ended up with 2 moles of SO3.

Total entropy at the end = 2(256.2) = 512.4 J K-1mol-1

entropy change = what you end up with - what you started with.

ΔS = entropy change = 512.4 J K-1mol-1 - 646.88 J K-1mol-1

= - 134.48 J K-1mol-1

Inputing the values into the formular, we have;

ΔG° = ΔH° - TΔS°

ΔG° = - 790400 - 298 (- 134.48)

ΔG° = - 790400 + 40075.04

ΔG° = -750324.96 J/mol = -750.324 Kj/mol

4 0

3 years ago

What is the molarity of a 50.0 mL solution that contains 0.0350 mol of sodium sulfate, Na2SO4?

Ymorist [56]

Answer:

The molarity of a 50.0 mL solution that contains 0.0350 mol of sodium sulfate 0.7 $\frac{moles}{liter}$

Explanation:

Molarity is a concentration measure that indicates the amount of moles of solute that appear dissolved in each liter of the mixture.

So, the Molarity of a solution is determined by the expression:

$Molarity (M)=\frac{number of moles of solute}{volume}$

Molarity is expressed in units ( $\frac{moles}{liter}$ ).

In this case:

number of moles= 0.0350

Volume=50 mL=0.05 L (1 L= 1,000 mL)

Replacing:

$Molarity=\frac{0.0350 moles}{0.05 L}$

Molarity= 0.7 $\frac{moles}{liter}$

The molarity of a 50.0 mL solution that contains 0.0350 mol of sodium sulfate 0.7 $\frac{moles}{liter}$

3 0

3 years ago