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7nadin3 [17]
3 years ago
8

Find AB. HELP PLEASEEEE, GIVING BRAINLIEST.

Mathematics
2 answers:
Damm [24]3 years ago
7 0
AB=10

The triangles are proportional. DC*2=AC. 12*2=24.

So DE*2=AB. 5*2=10
Arturiano [62]3 years ago
6 0

Answer:

AB = 10

Step-by-step explanation:

ΔABC ≈ ΔDEC

AB/5 = AC/DC

12AB = 120

AB = 120/12 or 10

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71 + 0 = 71 is an example of
Mrrafil [7]

Answer:

Identity Property (of 0)

Step-by-step explanation:

6 0
3 years ago
Evaluate 3x+y when x=1/3 and y=−7/4. Write your answer as a fraction in simplest form.
SOVA2 [1]

Answer:

3x+y

=3*1/3-7/4

=1-7/4

=(4-7)/4

=-3/4

6 0
3 years ago
Write each expression as an equivalent expression with a single logarithm. Assume xx, yy, and zz are positive real
Alekssandra [29.7K]

Answer:

\ln(\frac{xx + yy}{zz})^{\frac{1}{2}}

Step-by-step explanation:

Given:

1/2(ln(xx + yy) − ln(zz))

Now,

From the properties of log function,

1)  n × ln(x) = ln(xⁿ)

and,

2)  ln(A) - ln(B) = \ln\frac{A}{B}

applying the properties in the given equation

we get the above equation as:

\frac{1}{2}(\ln\frac{xx + yy}{zz})        

( using the property 2 we get (ln(xx + yy) − ln(zz) = \ln\frac{xx + yy}{zz}  

or

⇒ \ln(\frac{xx + yy}{zz})^{\frac{1}{2}}    ( using the property 1 i.e n × ln(x) = ln(xⁿ) )

expression as an equivalent expression with a single logarithm is \ln(\frac{xx + yy}{zz})^{\frac{1}{2}}

3 0
4 years ago
What are the slope and the y-intercept of the linear function that is represented by the equation y=9x-2?
Lilit [14]
The answer is b because the slope is 2 and the y intercept is 9
3 0
3 years ago
Read 2 more answers
the area of a rectangular window is 6216 cm^2. if the length of the window is 84 cm, what is it's width?​
Rus_ich [418]

Answer:

<h3>The answer is 74 cm</h3>

Step-by-step explanation:

The area of a rectangle = length × width

Since we are finding the width

We have

width  = \frac{area}{length}  \\

From the question

area = 6216 cm²

length = 84 cm

The width is

width =  \frac{6216}{84}  \\

We have the final answer as

<h3>74 cm</h3>

Hope this helps you

3 0
4 years ago
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