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creativ13 [48]
2 years ago
13

Consider the first six terms of this sequence: 2, 5, 8, 11, 14, 17,........What would be the 41st term of this sequence?

Mathematics
1 answer:
Neporo4naja [7]2 years ago
7 0

Answer:

122

Step-by-step explanation:

The nth term for this sequence is 3n - 1.

3 x 41 = 123

123 - 1 = 122

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