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Brilliant_brown [7]
3 years ago
10

Graph ​h(x)=3cos(2x)−1​. Use 3.14 for π.

Mathematics
1 answer:
Eva8 [605]3 years ago
4 0

Step-by-step explanation:

the answer is in the attachment

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The data below represents the number of minutes Jake and Sarah spent doing chores
hichkok12 [17]
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The median number of minutes for Jake and Sarah are equal, but the mean numbers are different.

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For this, you never said the choices, but I’ve done this before, so I’m going to use the answer choices I had, and hopefully they are right.

Our choices are -

• The median number of minutes for Jake is higher than the median number of minutes for Sarah.

• The mean number of minutes for Sarah is higher than the mean number of minutes for Jake.

• The mean number of minutes for Jake and Sarah are equal, but the median number of minutes are different.

• The median number of minutes for Jake and Sarah are equal, but the mean number of minutes are different.

————————

So to answer the question, we neee to find the median and mean for each data set, so -

Jack = [90 median] [89.6 mean]
Sarah = [90 median] [89.5 mean]

We can clearly see the median for both is 90, so we can eliminate all the choices that say they are unequal.

We can also see that Jack has a higher mean (89.6) compared to Sarah (89.5).

We can eliminate all the choices that don’t imply that too.

That leaves us with -

• The median number of minutes for Jake and Sarah are equal, but the mean number of minutes are different.
8 0
2 years ago
Jenn and David shared a candy bar. Jenn are three tenths. David ate four tenths. How much is left?
Sedbober [7]
The answer is 3 tenths
6 0
2 years ago
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Please help me I don't know it
ValentinkaMS [17]
I believe the answer would be a but im not certain
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3 0
3 years ago
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Can the mean value theorum be applied to the function f(x)=1/x^2 on the interval [-2, 1]? Explain.
Temka [501]

Answer:

No, it can not be applied.

Step-by-step explanation:

f(x) = 1/x²

f(x) is a polynomial that is not continuous

As,

f(x) = 1/0 is undefines

Secondly, it is not differentiable (i.e. the derivative does not exists on the interval given)

Derivative of this function

f'(x) = (1)x^-2

       = -2x^(-2-1)

       = -2x^(-3)

       = -2/x³

      =  -2/x³

f'(0) = -2/0 is undefined

Thus, mean value theorem can not be applied.

7 0
3 years ago
I NEED HELP ON THESE TWO QUESTIONS WHO EVER IS RIGHT GET BRAINLY :) !!!​
DedPeter [7]

Answer:

4 maybe, sry if im wrong

Step-by-step explanation:

3 0
3 years ago
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