Answer:
0.50 kg of the material would be left after 10 days.
0.25 kg of the material would be left after 20 days.
Step-by-step explanation:
We have been given that the half-life of a material is 10 days. You have one 1 kg of the material today. We are asked to find the amount of material left after 10 days and 20 days, respectively.
We will use half life formula.
, where,
A = Amount left after t units of time,
a = Initial amount,
t = Time,
h = Half-life.




Therefore, amount of the material left after 10 days would be 0.5 kg.





Therefore, amount of the material left after 20 days would be 0.25 kg.
Answer:
if you google (surface area of a cylinder) it lets you input the radius and height and it gives your answer
Step-by-step explanation:
Answer:
The equation of the line would be y = 1/5x + 6
Step-by-step explanation:
First, to find the slope of a perpendicular line, you need to find the opposite and reciprocal of the original slope. Since the original is -5, we first change the sign (which makes it just 5). Now we take that 5 and flip it to get 1/5.
Now that we have the slope as 1/5, we can use that and the intercept in slope-intercept form to get the equation.
y = mx + b
y = 1/5x + 6
I think the answer is (9,8)
Sqrt(9)÷25= 0.12 I hope this helps!