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victus00 [196]
2 years ago
13

Please help me asap thank you !!

Mathematics
1 answer:
jasenka [17]2 years ago
5 0

Answer:

x = 3

Step-by-step explanation:

Measure of a triangle is 180° degree.

.·. 46 + 105 + 6x + 11 = 180

.·. 162+6x=180

.·. 6x=180-162

.·. 6x= 18

.·. x= 18/6

.·. x= 3

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If you broke apart 56 in half, What plus what would you get?
frosja888 [35]

56 ÷ 2 = 28

28 + 28 = 56

<em>Have a luvely day!</em>

6 0
2 years ago
What is the sum of the first 10 terms of the sequence 2, 6, 18,54...?
leonid [27]

Answer:

This is a sequence where you <em>multiply that number 3 times</em>.  For example, 2 x 3 = <em>6</em>.  6 x 3 = <em>18</em>.  18 x 3 = <em>54</em> and so on.  Therefore, <em>multiplying 3 by the number is the Answer.</em>

<em></em>

4 0
3 years ago
Noah is making grilled cheese sandwiches for friends. He has 24 ounces of cheese. He plans to split the cheese evenly between 6
Marysya12 [62]

Answer:

24/6=c

Step-by-step explanation:

Well to split 24 you need to divide by 6 and that will equal the answer. An equation always has a equal sign so you know that you would be solving for c

3 0
2 years ago
Read 2 more answers
Arrange the geometric series from least to greatest based on the value of their sums.
son4ous [18]

Answer:

80 < 93 < 121 < 127

Step-by-step explanation:

For a geometric series,

\sum_{t=1}^{n}a(r)^{t-1}

Formula to be used,

Sum of t terms of a geometric series = \frac{a(r^t-1)}{r-1}

Here t = number of terms

a = first term

r = common ratio

1). \sum_{t=1}^{5}3(2)^{t-1}

   First term of this series 'a' = 3

   Common ratio 'r' = 2

   Number of terms 't' = 5

   Therefore, sum of 5 terms of the series = \frac{3(2^5-1)}{(2-1)}

                                                                      = 93

2). \sum_{t=1}^{7}(2)^{t-1}

   First term 'a' = 1

   Common ratio 'r' = 2

   Number of terms 't' = 7

   Sum of 7 terms of this series = \frac{1(2^7-1)}{(2-1)}

                                                    = 127

3). \sum_{t=1}^{5}(3)^{t-1}

    First term 'a' = 1

    Common ratio 'r' = 3

    Number of terms 't' = 5

   Therefore, sum of 5 terms = \frac{1(3^5-1)}{3-1}

                                                 = 121

4). \sum_{t=1}^{4}2(3)^{t-1}

    First term 'a' = 2

    Common ratio 'r' = 3

    Number of terms 't' = 4

    Therefore, sum of 4 terms of the series = \frac{2(3^4-1)}{3-1}

                                                                       = 80

    80 < 93 < 121 < 127 will be the answer.

4 0
2 years ago
Read 2 more answers
Solve the system of linear equations by substitution. Check your solution.
bearhunter [10]
1. X+2=3x-4
6=2x
x= 3

2. y= 8-x
8-x = 3x+4
4= 4x
X= 1

3. -2x +3(2x+7)=9
-2x + 6x + 21 = 9
4x = -12
x= -3
8 0
2 years ago
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