The solutions of x² = 16x - 28 are<br> 1) -2 and -14<br> 2) 2 and 14<br> 3) -4 and -7<br> 4) 4 and 7

Help me please explain on how to do this

Leviafan [203]

Answer:

Easy

Step-by-step explanation:

To find the perimeter, add all the sides together.

12+16+20=48

To find the area, you multiply the sides that make the right angle of the triangle,

12×16=192

And divide it by two. This step is important as if you don't divide it by two, you will end up with the area of a square.

192÷2=96

Finito. Oh and don't forget to add units.

Cm for perimeter and Cm(squared) for area. :)

7 0

3 years ago

B is the midpoint of AC, D is the midpoint of CE, and AE = 11. Find BD.

inessss [21]

Answer:

5.5

Step-by-step explanation:

B is the midpoint of AC, D is the midpoint of CE

This means that CE = 1/2 AE

CD = 1/2 ( 11)

CD = 5.5

6 0

2 years ago

State whether the following coordinates on a Cartesian plane form an acute, obtuse or right triangle: a) (-1, 1), (7,-2) and (1,

LiRa [457]

Answer:

a) Acute triangle

b) Right triangle

Step-by-step explanation:

∵ A triangle having sides a, b and c is called,

Acute : If a² + b² > c² or a² + c² > b² or b² + c² > a²,

Obtuse : if a² + b² < c² or a² + c² < b² or b² + c² < a²

Right : a² + b² = c² or a² + c² = b² or b² + c² = a²,

a) Let A≡(-1, 1), B≡(7,-2) and C≡(1,-5),

By the distance formula,

$AB=\sqrt{(7-(-1))^2+(-2-1)^2}=\sqrt{(7+1)^2+(-3)^2}=\sqrt{8^2+3^2}=\sqrt{64+9}=\sqrt{73}\text{ unit}$

Similarly,

$BC=\sqrt{45}\text{ unit}$

$CA=\sqrt{40}\text{ unit}$

∵ The sum of any two sides is greater than third side,

So, ABC is a triangle,

Now,

$AB^2 + BC^2 > CA^2$

⇒ ABC is an acute triangle.

b) Let P≡(0,6), Q≡(1,2) and R≡(5,3),

By the distance formula,

PQ = √17 unit,

QR = √17 unit,

RP = √34 unit,

∵ The sum of any two sides of PQR is greater than third side,

⇒ PQR is a triangle ,

Also,

$RP^2=PQ^2+QR^2$

Hence, PQR is a right triangle.

3 0

3 years ago

What is sin 49° to the nearest tenth

Ilia_Sergeevich [38]

Answer:

50

Step-by-step explanation:

50???

5 0

3 years ago

Read 2 more answers

(5n2 – 4nm - 9m²) + (7n2 + 4nm +8m²) =

Flauer [41]

Answer:

$\left(5n^2-4nm-9m^2\right)+\left(7n^2+4nm+8m^2\right)=12n^2-m^2$

Step-by-step explanation:

Given the expression

$\left(5n^2\:-\:4nm\:-\:9m^2\right)\:+\:\left(7n^2\:+\:4nm\:+8m^2\right)$

Remove parentheses: (a) = a

$=5n^2-4nm-9m^2+7n^2+4nm+8m^2$

Group like terms

$=5n^2+7n^2-4nm+4nm-9m^2+8m^2$

Add similar elements: $5n^2+7n^2=12n^2$

$=12n^2-4nm+4nm-9m^2+8m^2$

Add similar elements: $-4nm+4nm=0$

$=12n^2-9m^2+8m^2$

Add similar elements: $-9m^2+8m^2=-m^2$

$=12n^2-m^2$

Therefore, we conclude that:

$\left(5n^2-4nm-9m^2\right)+\left(7n^2+4nm+8m^2\right)=12n^2-m^2$

5 0

3 years ago

The solutions of x² = 16x - 28 are 1) -2 and -14 2) 2 and 14 3) -4 and -7 4) 4 and 7