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Elza [17]
3 years ago
11

Where can i find exams i need to pass to go to Harvard?

Mathematics
1 answer:
elixir [45]3 years ago
3 0
You can’t you have to take a picture of it then it tells you the answer
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Borrowed $250
Fittoniya [83]

Answer:

Total interest paid:

$83.73

Total payments:

$333.73

8 0
3 years ago
If f(x)=5x-1, then f^1(x)=
nordsb [41]

Answer:

(y+1)/5

Step-by-step explanation:

you meant f^-1(x) ?

let y= 5x-1

Make x subject of formula

y+1=5x

x=(y+1)/5

f^-1(x)=(x+1)/5 replace y by x

3 0
3 years ago
Find the lateral area of the regular pyramid<br><br> L.A. =
Arisa [49]

Answer:

FOR REGULAR PYRAMID with those dimension.

L.A = 96

FOR HEXAGONAL PYRAMID with those dimension

L.A = 171.71

Step-by-step explanation:

Please the question asked for L.A of a REGULAR PYRAMID, but the figure is a HEXAGON PYRAMID.

Hence I solved for both:

FOR REGULAR PYRAMID

Lateral Area (L.A) = 1/2* p * l

Where p = Perimeter of base

P = 4s

P = 4 * 6

P = 24cm

l = slanted height

l = 8cm

L.A = 1/2 * 24 * 8

L.A = 1/2 ( 192)

L.A = 96cm ^ 2

FOR AN HEXAGONAL PYRAMID

Lateral Area = 3a √ h^2 + (3a^2) / 4

Where:

a = Base Edge = 6

h = Height = 8

L.A = 3*6 √ 8^2 + ( 3*6^2) / 4

L.A = 18 √ 64 + ( 3 * 36) / 4

L.A = 18 √ 64 + 108/4

L.A = 18 √ 64+27

L.A = 18 √ 91

L.A = 18 * 9.539

L.A = 171.71

8 0
3 years ago
Solve for X. <br><br> <img src="https://tex.z-dn.net/?f=log_%7B8%7D%20x-log_%7B8%7D%20%28-2x%2B4%29%20%3D%20log_%7B8%7D%203" id=
taurus [48]

Answer: x=\frac{12}{7}

Step-by-step explanation:

Remember the logarithms properties:

log(m)-log(n)=log(\frac{m}{n})\\\\b^{log_b(a)}=a

Then,simplifying:

log_{8}(\frac{x}{-2x+4}) = log_{8}(3)

Apply base 8 to boths sides and then solve for "x":

8^{log_{8}(\frac{x}{-2x+4})}=8^{log_{8}(3)}\\\\\frac{x}{-2x+4}=3\\\\x=3(-2x+4)\\\\x=-6x+12\\x+6x=12\\7x=12\\\\x=\frac{12}{7}

4 0
3 years ago
Read 2 more answers
All my points + Brainliest, pls help.
Sever21 [200]

Answer: 2x - 1 > 0 ( x = 1)

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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