Answer:
x = 6
x = -1
x = 1
Step-by-step explanation:
Given:
Correct equation;
P(x) = x³ - 6x² - x + 6
Computation:
x³ - 6x² - x + 6
x²(x-6)-1(x-6)
(x-6)(x²-1)
we know that;
a²-b² = (a+b)(a-b)
So,
(x-6)(x²-1)
(x-6)(x+1)(x-1)
So,
zeroes are;
x = 6
x = -1
x = 1
Answer:
True. See the explanation and proof below.
Step-by-step explanation:
For this case we need to remeber the definition of linear transformation.
Let A and B be vector spaces with same scalars. A map defined as T: A >B is called a linear transformation from A to B if satisfy these two conditions:
1) T(x+y) = T(x) + T(y)
2) T(cv) = cT(v)
For all vectors
and for all scalars
. And A is called the domain and B the codomain of T.
Proof
For this case the tranformation proposed is t:
Where
For this case we have the following assumption:
1) The transpose of an nxm matrix is an nxm matrix
And the following conditions:
2) 
And we can express like this 
3) If
and
then we have this:

And since we have all the conditions satisfied, we can conclude that T is a linear transformation on this case.
Since its to the tenth power and the exponent is negative all you have to do is move the decimal point two positions back and your new answer is 0.382
Answer: (a)
(b) 
Step-by-step explanation:
(a) P( Bill hitting the target) = 0.7 P( Bill not hitting the target) = 0.3
P( George hitting the target) = 0.4 P(George not hitting the target) = 0.6
Now the chances that exactly one shot hit the target is = 0.7 x 0.6 + 0.4 x 0.3
= 0.54
Chances that George hit the target is = 0.4 x 0.3 = 0.12
So given that exactly one shot hit the target, probability that it was George's shot =
=
.
(b) The numerator in the second part would be the same as of (a) part which is 0.12.
The change in the denominator will be that now we know that the target is hit so now in denominator we include the chance of both hitting the target at same time that is 0.4 x 0.7 and the rest of the equation is same as above i.e.
Given that the target is hit,probability that George hit it =
= =