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jasenka [17]
2 years ago
13

Last year, Gilbert contributed $75 toward his 401(k) account each month. If his employer matched 16% of his contributions, what

was the total amount contributed to the 401(k) at the end of the year?
Mathematics
2 answers:
Levart [38]2 years ago
7 0

Answer:

$1044 was contributed.

Step-by-step explanation:

Last year, Gilbert contributed toward his 401(k) account each month = $75.00

Contribution in a year = $75.00 × 12 = $900.00

His employer matched 16% of his contribution

Employer's contribution = 16% of $900.00

\frac{16}{100} × 900

= 0.16 × 900 = $144.00

Total contribution = $900 + $144 = $1044

The total amount $1044 was contributed to the 401(k) at the end of the year.

Darya [45]2 years ago
5 0
$75 to his 401k each month......75(12) = 900 in a yr.
his employee matched 16% of his contributions..
16% of 900 =
0.16(900) = 144

so the total amount contributed was : 900 + 144 = $ 1044
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Four plumbers estimated the length of the radius of a cylindrical pipe. The estimates made by
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Answer:

B. \frac{\sqrt{3}}{11}, \frac{\pi}{24}, \frac{3}{25},  \frac{9}{100}

Step-by-step explanation:

The question is not properly presented. See attachment for proper presentation of question

From the attachment, we have that:

W = \frac{3}{25}

X = \frac{\sqrt{3}}{11}

Y = \frac{9}{100}

Z = \frac{\pi}{24}

Required

Order from greatest to least

First, we need to simplify each of the given expression (in decimals)

W = \frac{3}{25}

W = 0.12

X = \frac{\sqrt{3}}{11}

Take square root of 3

X = \frac{1.73205080757}{11}

X = 0.15745916432

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Y = \frac{9}{100}

Y = 0.09

Z = \frac{\pi}{24}

Take π as 3.14

Z = \frac{3.14}{24}

Z = 0.13083333333

Z = 0.13  --- approximated

List out the results, we have:

W = 0.12    X = 0.16    Y = 0.09    Z = 0.13

Order from greatest to least, we have:

X = 0.16     Z = 0.13      W = 0.12       Y = 0.09

Hence, the order of arrangement is:

X = \frac{\sqrt{3}}{11}     Z = \frac{\pi}{24}      W = \frac{3}{25}      Y = \frac{9}{100}

i.e.

\frac{\sqrt{3}}{11}, \frac{\pi}{24}, \frac{3}{25},  \frac{9}{100}

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