- Determine the surface area of the right square pyramid.
The formula for finding the surface area of a right square pyramid is ⇨ b² + 2bl, where
- b = base of the right square pyramid
- l = slant height of the right square pyramid.
In the given figure,
- base (b) = 4 ft.
- slant height (l) = 8 ft.
Now, let's substitute the values of b & l in the formula & solve it :-
So, the surface area of the right square pyramid is <u>8</u><u>0</u><u> </u><u>ft²</u><u>.</u>
Hello there!
the solutions to this system of inequalities are every point in the blue area. In order to figure out if each of those choices are solutions, just graph the points, and if they are in the blue, they are solutions.
Using this method, you get A and C as your answers because they are in the blue region.
I really hope this helps!
Best wishes :)
Short Answer: AB
Argument
Take F to be the center. The line segment that IS a diameter or radius must either go through F (that would make the line a diameter) or to be a radius the segment mus end in F and touch the circumference once. See below.
The diameter must not only go through F, it must touch the circumference in two places. EFB is a diameter. So is AFC
The radius must have 1 endpoint at the center and one endpoint on the circumference. DF is a radius.
So what isn't? Answer: AB isn't. It neither goes through F nor is F one of the end points.
Answer: AB
The value of p(3) is is 3