B and C trisect AD and M is the midpoint of AD. MC=8. How many units are in the length of AD?

Mathematics

1 answer:

sineoko [7]2 years ago

4 0

Answer:

Step-by-step explanation:

B and C trisrct AD so

that means that

AB=BC=CD

M is the midpoint so AM =MD

M is also the midpoint of BC also so if MC equal 8 l, BM equal 8. We add 8 and 8 together to find the value of BC which equal 16. Since BC equal 16 and it trisects AD, AB equal 16 and CD equal 16. Add all together and we get 16+16+16=16×3=48

You might be interested in

Answer please! (No explanation needed!) <3

son4ous [18]

Hi there! Hopefully this helps!

----------------------------------------------------------------------------------------------

Question A answer: 2.

To find the median, you simply need to order the set from lowest to highest and finding the exact middle. So it should look like this:

0, 1, 2, 3, 4. So 2 is the median, therefore 2 is the answer to Question A.

------------------------------------------------------------------------------------------------

Question B answer: 2

To find the mean, you have to add all of the numbers together and then you have to divide by the number of items in the set. There are 5 numbers in the set so it should look like this:

0 + 1 + 2 + 3 + 4 = 10.

Since there 5 numbers in the set, we need to divide by 5.

10 / 5 = 2.

Therefore, 2 is also the answer to Question B.

-------------------------------------------------------------------------------

Edit: Whoops, sorry for the explanation...

5 0

2 years ago

Read 2 more answers

I am posting my work for an application of integrals problem. I would love to know if anyone else agrees with my work!

quester [9]

Your work appears to be correct.

The results from a graphing calculator are in agreement.