What we have so far:
Kinetic energy = 0. The reason behind that is because the beam is not moving at a height of 40m.
Gavity, g = 9.8m/s²
Height = 40m
Potential energy = mgh; this is equal to 0 because m, stands for mass and in this problem, we do not have a value for the mass of the beam. Hence, 0 x 9.8m/s² x 40m = 0. Potential energy = 0.
Solution:
We will use the equation of Total energy:
TE = potential energy + kinetic energy
TE = 0 + 0
∴ TE = 0
The answer is: Assuming no air resistance, the total energy of the beam as it hits the ground is 0.
When al of the 10 pages are filled with 40 stickers
The best part of this problem is that it has one unknown variable in the form of "x" and a single equation. So getting to the desired solution becomes very easy.
The equation given in the question is
10 - 5x = 20
- 5x = 20 - 10
- 5x = 10
- x = 10/5
- x = 2
Multiplying both sides with -1 we get
x = -2
So the value of x is -2. I hope the procedure is clear enough for you to understand.
Step-by-step explanation:
id-9384026088
password -1234
Answer:
50 dollars
Step-by-step explanation: 99.99 plus 23.51 = 123.5. 123.5 minus 73.50 = 50
