solution:
P(passed)=P(Dr. J and passed)+P(Dr. S and passed) =0.4*0.8+(1-0.4)*0.6=0.68
hence probability that she was enrolled in Dr. J's section given passed
=P(Dr. J and passed)/P(passed)=0.4x0.8/0.68=0.4706
Answer:
3. x=50, y=80, 4. x=6.5, y=5
Step-by-step explanation:
I think, not entirely sure.
Answer:
I don't exactly know what the question is here
X+40+134=180
X+174=180 (combine like terms)
X=6 (subtract)
Add up all the numbers then divide how many ever digits there are
