Answer:
Quizlet is pretty good!
Step-by-step explanation:
It's a linear function. We need only two points to draw a graph.
We choose any values of x and calculate the value of y.
![6x-2y=2\qquad|-6x\\\\-2y=-6x+2\qquad|:(-2)\\\\y=3x-1](https://tex.z-dn.net/?f=6x-2y%3D2%5Cqquad%7C-6x%5C%5C%5C%5C-2y%3D-6x%2B2%5Cqquad%7C%3A%28-2%29%5C%5C%5C%5Cy%3D3x-1)
for x= 0 → y = 3(0) - 1 = 0 - 1 = -1 → (0, -1)
for x = 2 → y = 3(2) - 1 = 6 - 1 = 5 → (2, 5)
![9x-3y=1\qquad|-9x\\\\-3y=-9x+1\qquad|:(-3)\\\\t=3x-\dfrac{1}{3}](https://tex.z-dn.net/?f=9x-3y%3D1%5Cqquad%7C-9x%5C%5C%5C%5C-3y%3D-9x%2B1%5Cqquad%7C%3A%28-3%29%5C%5C%5C%5Ct%3D3x-%5Cdfrac%7B1%7D%7B3%7D)
for x = 0 → y = 3(0) - 1/3 = 0 - 1/3 = -1/3 → (0, -1/3)
for x = 2 → y = 3(2) - 1/3 = 6 - 1/3 = 5 2/3 → (2, 5 2/3)
5.7n = 2.96-4.1
5.7n = -1.14
n= -1.14/5.7
n = -0.2
Answer: Choice A) All points with an x-value of 3 are located in Quadrant I.
We can show it is false through the use of a counter example. For instance, the point (3, -5) is not in quadrant 1, but rather in quadrant 4.
We would need to say "all points with x value 3 and positive y value" to ensure the point is in quadrant 1.
Answer:
-6/4 or -1.5
Step-by-step explanation:
because they have the same denominator, this would basically be (-3-3)/4
this can be reduced to -6/4, or -1.5