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lakkis [162]
3 years ago
8

Factor the following expression

" alt="x^{2} -7x-18" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
guapka [62]3 years ago
4 0

Answer:

(x-9) (x=2)

Step-by-step explanation:

You might be interested in
How to cross multiple 3/5 by 10
Vika [28.1K]

Here is you're answer:

In order to cross multiply you have to multiply the numerator and denominator of the first fraction by the bottom number of the second fraction and see if the equation is still true:

  • \frac{3}{5} \times 10
  • \frac{3}{5} \times \frac{10}{1}
  • 3 \times 1 = 5 \times 10
  • Solve if you like:
  • 3 \times 1 = 3
  • 5 \times 10 = 50
  • = \frac{4}{50}

Therefore you're answer is "3 × 1 = 5 × 10."

Hope this helps!

4 0
3 years ago
Find the distance between these points. <br> A(5,8), B(-3,4)
konstantin123 [22]

Answer:

<u>Distance</u><u> </u><u>between</u><u> </u><u>the</u><u> </u><u>points</u><u> </u><u>is</u><u> </u><u>8</u><u>.</u><u>9</u><u>4</u><u> </u><u>units</u>

Step-by-step explanation:

General formula:

{ \boxed{ \bf{distance =  \sqrt{ {(x_{1} - x _{2} )}^{2} +  {(y _{1} - y _{2} ) }^{2}  } }}}

substitute:

{ \sf{ =  \sqrt{ {(5 - ( - 3))}^{2}  +  {(8 - 4)}^{2} } }} \\  = {  \sf{ \sqrt{64 + 16} }} \\  = { \sf{ \sqrt{80} }} \\  = 8.94 \: units

{ \underline{ \sf{ \blue{christ \: † \: alone}}}}

6 0
3 years ago
Read 2 more answers
What is the least number of solution a quadratic system can have
Setler79 [48]
The least number of quadratic system can have is Two real solutions or no real solutions. 
8 0
3 years ago
Simplify. -3.7(4p - 7
Alchen [17]

Answer:

-14.8p+25.9

Step-by-step explanation:

got it right edge 2020.

3 0
3 years ago
A clerk at Agency Y has determined that at speeds of 25 pages per minute it is typical for 3 out of every 100 pages she photocop
nalin [4]

Answer:

180 pages

Step-by-step explanation:

Since her photocopy session is 25 pages per minute, the total number of pages photocopied in 4 hour session can be calculated as;

number of pages = time × speed

                                 = (4 × 60) × 25

                                 = 240 ×25

                                 = 6000 pages

Thus, number of pages photocopied in 4 hours is 6000.

For every 100 pages, 3 would contain some type of printing error. The number of pages she expect with printing error during 4 hour session can be determined as;

           = \frac{6000}{100} × 3

           = 60 × 3

           = 180 pages

The expected number of pages with printing error during 4 hour photocopying session is 180 pages.

3 0
3 years ago
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