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snow_tiger [21]
3 years ago
9

a __ is the amount of heat needed to raise the temperature of one kilogram of water one degree centigrade.

Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
5 0
A Calorie is the unit of energy required.
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-5/12+5/8 what is the answer to this
enot [183]

Answer:

5/24

Step-by-step explanation:

-5/12+5/8

-10/24+15/24

5/24

3 0
2 years ago
What is the gcd of 2563 and 4147
sdas [7]

Answer:

GCD=11

Step-by-step explanation:

Factors of 2563 are: 1 , 11 , 233 , 2563.

Factors of 4147 are: 1 , 11 , 13 , 29 , 143 , 319 , 377 , 4147.




7 0
3 years ago
Long division 7÷688 remainder of what and the answerand what steps how to do it
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Here are the steps on how I did it.

6 0
3 years ago
Only answer the second one please
KengaRu [80]
Equation is: y=5/6x+8
5 0
3 years ago
Read 2 more answers
Help. I need help with these questions ( see image).<br> Please show workings.
Andrew [12]

9514 1404 393

Answer:

  4)  6x

  5)  2x +3

Step-by-step explanation:

We can work both these problems at once by finding an applicable rule.

  \text{For $f(x)=ax^n$}\\\\\lim\limits_{h\to 0}\dfrac{f(x+h)-f(x)}{h}=\lim\limits_{h\to 0}\dfrac{a(x+h)^n-ax^n}{h}\\\\=\lim\limits_{h\to 0}\dfrac{ax^n+anx^{n-1}h+O(h^2)-ax^n}{h}=\boxed{anx^{n-1}}

where O(h²) is the series of terms involving h² and higher powers. When divided by h, each term has h as a multiplier, so the series sums to zero when h approaches zero. Of course, if n < 2, there are no O(h²) terms in the expansion, so that can be ignored.

This can be referred to as the <em>power rule</em>.

Note that for the quadratic f(x) = ax^2 +bx +c, the limit of the sum is the sum of the limits, so this applies to the terms individually:

  lim[h→0](f(x+h)-f(x))/h = 2ax +b

__

4. The gradient of 3x^2 is 3(2)x^(2-1) = 6x.

5. The gradient of x^2 +3x +1 is 2x +3.

__

If you need to "show work" for these problems individually, use the appropriate values for 'a' and 'n' in the above derivation of the power rule.

3 0
3 years ago
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