Question

A manufacturer of matches randomly and independently puts 15 matches in each box of matches produced. The company knows that one-tenth of 6 percent of the matches are flawed. What is the probability that a matchbox will have one or fewer matches with a flaw?
a) 0.005515
b) 0.006704
c) 0.9940
d) 0.9137
e) 0.9964
f) None of the above

Answer 1

Answer:

e) 0.9964

Step-by-step explanation:

6% = 0.06

One tenth of 6% = 0.006

X ~ B(15, 0.006)

q = 1 - 0.006 = 0.994

P(X = 0, 1)

(15C1×0.006×0.994¹⁴) + 0.994¹⁵

= 0.9964113451