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Feliz [49]
3 years ago
15

Luca is planning to pay the restaurant bill for his coworkers. The bill was $193.75. A 4% tax was then added by the waiter. If L

uca wants to leave a 16% tip on the total amount including the tax, how much should Luca pay?
Mathematics
2 answers:
Zigmanuir [339]3 years ago
7 0

Answer:

$201.50

Step-by-step explanation:

just took the. test

horrorfan [7]3 years ago
4 0

Answer:

If Luca wants to leave a 16% tip on the total amount including the tax, he should pay $32.24.

Step-by-step explanation:

First, you have to calculate the 4% of the bill and add that amount to the total of the bill to determine the total amount including the tax:

193.75¨*4%=7.75

193.75+7.75=201.5

Now, you have to calculate 16% of the amount including the tax:

201.5*16%=32.24

According to this, the answer is that if Luca wants to leave a 16% tip on the total amount including the tax, he should pay $32.24.

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Divide 2y2 + 8 by 2y + 4. Which expression represents the quotient and remainder?
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When 2(y^2) + 8 is divided by  2y + 4 is equal to (y - 2) + (16 / (2y + 4)). The expression represents the quotient is the 2y + 4. While the expression represent the remainder is 16 / (2y + 4). The remainder of the given expression can also be solve using the remainder theorem. 

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8/10 > 3/4 > -3/4 > -7/10

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The time needed to complete a final examination in a particular college course is normallydistributed with a mean of 80 minutes
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Answer:

a) 0.023

b) 0.286

c) 10 students will be unable to complete the exam inthe allotted time.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 80 minutes

Standard Deviation, σ = 10 minutes

We are given that the distribution of time to complete an exam is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(completing the exam in one hour or less)

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P( x < 60) = P( z < \displaystyle\frac{60 - 80}{10}) = P(z < -2)

Calculation the value from standard normal z table, we have,  

P(x < 60) =0.023= 2.3\%

b) P(complete the exam in more than 60 minutes but less than 75 minutes)

P(60 \leq x \leq 75) = P(\displaystyle\frac{60 - 80}{10} \leq z \leq \displaystyle\frac{75-80}{10}) = P(-2 \leq z \leq -0.5)\\\\= P(z \leq -0.5) - P(z < -2)\\= 0.309- 0.023 = 0.286= 28.6\%

c) P(completing the exam in more than 90 minutes)

P(x > 90)

P( x > 90) = P( z > \displaystyle\frac{90 -80}{10}) = P(z > 1)

= 1 - P(z \leq 1)

Calculation the value from standard normal z table, we have,  

P(x > 90) = 1 - 0.8413 = 0.1587 = 15.87\%

15.87% of children of class will require more than 90 minutes to complete the test.

Number of children =

\dfrac{15.87}{100}\times 60 = 9.52\approx 10

Approximately, 10 students of class will require more than 90 minutes to complete the test.

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