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mars1129 [50]
3 years ago
11

Jacob rode his bike 5 3/4 miles last week. This week,he rode 4 times as far as he rode last week. How many miles did Jacob ride

his bike this week?
Mathematics
2 answers:
Fudgin [204]3 years ago
6 0

Answer:

5 3/4 times 4 = 23/4 times 4 = 92/4 =23

Step-by-step explanation:

Bess [88]3 years ago
4 0

Answer:

Hope this helps

Step-by-step explanation:

1. Make 5 3/4 into an improper fraction. That would be 23/4. 2. Write 4 in a fraction way. That would be 4/1. 3. Now do 23/4 X 4/1. That would be 92/4. 4. Turn it into a mixed number by doing 92 divided by 4. That would be 23. No fraction after 23. Jacob rode his bike 23 miles this week. :)

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8 0
4 years ago
Set up but do not solve for the appropriate particular solution yp for the differential equation y′′+4y=5xcos(2x) using the Meth
taurus [48]

Answer:

So, solution of  the differential equation is

y(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos  2x+c_1e^{-2it}+c_2e^{2it}\\

Step-by-step explanation:

We have the given differential equation: y′′+4y=5xcos(2x)

We use the Method of Undetermined Coefficients.

We first solve the homogeneous differential equation y′′+4y=0.

y''+4y=0\\\\r^2+4=0\\\\r=\pm2i\\\\

It is a homogeneous solution:

y_h(t)=c_1e^{-2i t}+c_2e^{2i t}

Now, we finding a particular solution.

y_p(t)=A5x\cos 2x\\\\y'_p(t)=A5\cos 2x-A10x\sin 2x\\\\y''_p(t)=-A20\sin 2x-A20x\cos 2x\\\\\\\implies y''+4y=5x\cos 2x\\\\-A20\sin 2x-A20x\cos 2x+4\cdot A5x\cos 2x=5x\cos 2x\\\\-A20\sin 2x=5x\cos 2x\\\\A=-\frac{x}{4} \cot 2x\\

we get

y_p(t)=A5\cos 2x\\\\y_p(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos  2x\\\\\\y(t)=y_p(t)+y_h(t)\\\\y(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos  2x+c_1e^{-2it}+c_2e^{2it}\\

So, solution of  the differential equation is

y(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos  2x+c_1e^{-2it}+c_2e^{2it}\\

7 0
3 years ago
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Step-by-step explanation:

see the attached figure to better understand the problem

we know that

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equate equation A and equation B

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oksian1 [2.3K]

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