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andrezito [222]
3 years ago
9

(08.03 MC)

Mathematics
2 answers:
tester [92]3 years ago
7 0
The trick here is to notice that all 3 terms can be div. by 2:

2(x^2 + x - 12)

Note that -12 factors into -3 * 4 or -4 * 3.  Thus,

x^2 + x - 12 = (x-4)(x+3), and so <span>2x2 + 2x − 24 = 2(x-4)(x+3).</span>
masya89 [10]3 years ago
4 0

Answer:

2(x − 3)(x + 4)

Step-by-step explanation:

We have to factor the expression 2x^2+2x-24

Factor out GCF which is 2

2(x^2+x-12)

We can write the middle term as : x = 4x-3x

2(x^2+4x-3x-12)

Now, we factor out GCF as follows

2(x(x+4)-3(x+4))

Now, factored out the common term

2((x+4)(x-3))

First option is correct.

Factored form is given by 2(x − 3)(x + 4)

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For a criminal trial, 8 active and 4 alternate jurors are selected. Two of the alternate jurors are male and two are female. Dur
aleksley [76]

Answer:

The answer would be 1/6

6 0
3 years ago
Which of the following expressions is equivalent to?
gayaneshka [121]

Answer:  

It's the last choice:  2x^2 - 5x - 8 - 37/(x - 5).

Step-by-step explanation:

Long division:

        2x^2 - 5x -8    <---------------Quotient

        ---------------------------------

x - 5 ) 2x^3 - 15x^2 + 17x + 3

          2x^3 - 10x^2

                     - 5x^2 + 17x

                     - 5x^2  + 25x

                                   - 8x + 3

                                   - 8x + 40

                                           -37 <------ Remainder.

7 0
2 years ago
1 kg = 2.2lb<br><br> 6.3lb = ___kg<br> show work
poizon [28]
\dfrac{1kg}{xkg}=\dfrac{2.2lb}{6.3lb}\ \ \ \ |cross\ multiply\\\\2.2x=1\cdot6.3\\\\2.2x=6.3\ \ \ |divide\ both\ sides\ by\ 2.2\\\\x=\dfrac{6.3}{2.2}\\\\x=\dfrac{63}{22}\\\\\boxed{6.3lb=2\frac{19}{22}kg\approx2.86kg}
4 0
2 years ago
Add 7 to me. Then subtract 10. If you subtract 5 and then add 9, you get 14. What number am I?
Vesna [10]

Answer:

your answer is 13.

am I correct.

3 0
3 years ago
Factor using the trinomial<br> 10.<br> X2 + 13x + 12
Rudik [331]

Answer:

Factoring the trinomial: x^2+13x+12 we get the factors \mathbf{(x+1)(x+12)}

Step-by-step explanation:

We need to factor the trinomial: x^2+13x+12

We can factor the trinomial by breaking the middle term i.e 13x

Such that adding or subtracting gets the both terms we get 13x and multiplying both terms we get 12x^2

We can break 13x as: 12x and x

Adding them we get 13x and multiplying them we get 12x^2

So,

x^2+13x+12\\=x^2+12x+x+12\\=x(x+12)+1(x+12)\\=(x+1)(x+12)

So, Factoring the trinomial: x^2+13x+12 we get the factors \mathbf{(x+1)(x+12)}

8 0
2 years ago
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