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Ierofanga [76]
3 years ago
12

I will give BRAINLIEST to the correct answer Find the measure of

Mathematics
1 answer:
xxMikexx [17]3 years ago
7 0

Answer:

<em>8</em><em>y</em><em>+</em><em>5</em><em>7</em><em>+</em><em>2</em><em>y</em><em>+</em><em>8</em><em>3</em><em> </em><em>=</em><em>1</em><em>8</em><em>0</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>1</em><em>0</em><em>y</em><em>+</em><em>1</em><em>4</em><em>0</em><em>=</em><em>1</em><em>8</em><em>0</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>1</em><em>0</em><em>y</em><em> </em><em>=</em><em>1</em><em>8</em><em>0</em><em>-</em><em>1</em><em>4</em><em>0</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>1</em><em>0</em><em>y</em><em> </em><em>=</em><em>4</em><em>0</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>y</em><em> </em><em>=</em><em>4</em>

<em>CPH</em><em>=</em><em>2</em><em>y</em><em>+</em><em>8</em><em>3</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>8</em><em>+</em><em>8</em><em>3</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>9</em><em>1</em>

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Answer:

y = - \frac{1}{2}

Step-by-step explanation:

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3 years ago
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3 years ago
How do you do this question?
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Answer:

V = 2000r³/3

Step-by-step explanation:

We know that the base is a circular disk, so it creates a circle on the xy plane. It would be in the form x² + y² = r². In other words x² + y² = (5r)². Let's isolate y in this equation now:

x² + y² = (5r)²,

x² + y² = 25r²,

y² = 25r² - x²,

y = √25r² - x² ---- (1)

Now remember that parallel cross sections perpendicular to the base are squares. Therefore Area = length^2. The length will then be = 2√25r² - x² --- (2). Now we can evaluate the integral from -5r to 5r, of [ 2√25r² - x² ]² dx.

\int _{-5r}^{5r}\:\left[\:2\sqrt{\left(25r^2\:-\:x^2\right)}\:\right]\:^2\:dx\\=\int _{-5r}^{5r}4\left(25r^2-x^2\right)dx\\\\= 4\cdot \int _{-5r}^{5r}25r^2-x^2dx\\\\= 4\left(\int _{-5r}^{5r}25r^2dx-\int _{-5r}^{5r}x^2dx\right)\\\\= 4\left(250r^3-\frac{250r^3}{3}\right)\\\\= 4\cdot \frac{500r^3}{3}\\\\= \frac{2000r^3}{3}

As you can see, your exact solution would be, V = 2000r³/3. Hope that helps!

3 0
3 years ago
What is 60x-150=30?<br> (This is all the info I have for this question sorry!)
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60x - 150 = 30
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60x = 180
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x = 3
4 0
4 years ago
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