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Doss [256]
3 years ago
11

What is the image of E for a dilation with center (0, 0) and a scale factor of 6?

Mathematics
1 answer:
DochEvi [55]3 years ago
8 0
(-30,6) im pretty sure

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48c + 12 = 12(_______)
inn [45]

Answer:

\large\boxed{12(4c+1)}

Step-by-step explanation:

How to factor expressions?

Find the G.C.F. and divide it into the terms of the expression you need to factor, like this:

48c+12=12(4c+1)}. So I took the 12 and pulled it out of both terms, obtaining 12(4c+1).

3 0
1 year ago
I need help fast please I don’t understand this and I’ve been struggling for a while. Can I get a brain list please or a tutor t
solong [7]

Answer:

4 √6

Step-by-step explanation:

We have a few right triangles. We know that a²+b²=c², with c being the side opposite the right angle. Representing the side without a value as z, we have:

m²+z² = (8+4)² = 12²

4²+n²=z²

8²+n²=m²

We have 3 equations with 3 unknown variables, so this should be solvable. One way to find a solution is to put everything in terms of m and go from there. First, we can take n out of the equations entirely, removing one variable. We can do this by solving for it in terms of z and plugging that into the third equation, removing a variable as well as an equation.

4²+n²=z²

subtract 4²=16 from both sides

z²-16 = n²

plug that into the third equation

64 + z² - 16 = m²

48 + z² = m²

subtract 48 from both sides to solve for z²

z² = m² - 48

plug that into the first equation

m² + m² - 48 = 144

2m² - 48 = 144

add 48 to both sides to isolate the m² and its coefficient

192 = 2m²

divide both sides by 2 to isolate the m²

96 = m²

square root both sides to solve for m

√96 = m

we know that 96 = 16 * 6, and 16 = 4², so

m = √96 = √(4²*6) = 4 √6

5 0
2 years ago
Use Lagrange multipliers to find the maximum and minimum values of
marusya05 [52]

The Lagrangian is

L(x,y,\lambda)=x+8y+\lambda(x^2+y^2-4)

It has critical points where the first order derivatives vanish:

L_x=1+2\lambda x=0\implies\lambda=-\dfrac1{2x}

L_y=8+2\lambda y=0\implies\lambda=-\dfrac4y

L_\lambda=x^2+y^2-4=0

From the first two equations we get

-\dfrac1{2x}=-\dfrac4y\implies y=8x

Then

x^2+y^2=65x^2=4\implies x=\pm\dfrac2{\sqrt{65}}\implies y=\pm\dfrac{16}{\sqrt{65}}

At these critical points, we have

f\left(\dfrac2{\sqrt{65}},\dfrac{16}{\sqrt{65}}\right)=2\sqrt{65}\approx16.125 (maximum)

f\left(-\dfrac2{\sqrt{65}},-\dfrac{16}{\sqrt{65}}\right)=-2\sqrt{65}\approx-16.125 (minimum)

5 0
3 years ago
What are the angles of rotation for a 20-gon?
Basile [38]
There are 360 degrees so divide 360 by 20 and get 18 degrees
4 0
3 years ago
Read 2 more answers
the cost of a small cup of coffee at a deli is $3.50. You can use the equation t=3.5n, where t represents the total money made f
Kazeer [188]
3.5, it is the coefficient and describes how many n there are
3 0
2 years ago
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