First we need to write the null and alternate hypothesis for this case.
Let x be the average number of text message sent. Then
Null hypothesis: x = 100
Alternate hypothesis: x > 100
The p value is 0.0853
If p value > significance level, then the null hypothesis is not rejected. If p value < significance level, then the null hypothesis is rejected.
If significance level is 10%(0.10), the p value will be less than 0.10 and we reject the null hypothesis and CAN conclude that:
The mean number of text messages sent yesterday was greater than 100.
If significance level is 5%(0.05), the p value will be greater than 0.05 and we cannot reject the null hypothesis and CANNOT conclude that:
The mean number of text messages sent yesterday was greater than 100.
Answer:
There's not enough information to answer the question.
Step-by-step explanation:
The question says that out of 84 kids, 3/7 bought their lunches. Then it asks how many of the 3/7 got pizza without providing a number of those who bought a different food. And so, there's not enough information to solve this question.
17.46% of 126 is 22
Divide 22 by 126:
Change the decimal into a percentage by multiplying the decimal by 100:
Answer:
<h2>182.91 %</h2>
Step-by-step explanation:
<h3>spoiler alert: its 182.91 %</h3>
