Answer:
<u>Statements (1) and (2) TOGETHER are NOT sufficient.</u>
Explanation:
As in the equation (327)(510)(z) = (58)(914)(xy) there are THREE variables in total i.e. "x", "y" and "z" hence minimum three equations are required to find out values of all variables. Hence,
If the given number of equations is equal to total variable used in any of the equation, values of all the variables can be find out otherwise there can be unlimited number of solutions.
So, value of "x" cannot be determined with the given data.
Now, we know that 90°< θ <180°, that simply means the angle θ is in the II quadrant, where sine is positive and cosine is negative.

Answer:
(x-5) (x+4)
Step-by-step explanation:
x^2-x-20
What two terms multiply to -20 and add to -1
-5*4 = -20
-5+4 = -1
(x-5) (x+4)
The correct description of the graph:
<em>"One curve opens up and to the right in quadrant 1, and the other curve down and to the left in </em><em>quadrants </em><em>2, 1, and 4."</em>
<h3>
Which graph is the graph of the given functions?</h3>
Here we have the function:

The graph of this function can be seen below:
Then we can see that a curve opens up on quadrant 1, and down on quadrants 2 and 3 (it pass throw quadrant 1 for a little bit).
Then the correct option is:
<em>"One curve opens up and to the right in </em><em>quadrant </em><em>1, and the other curve down and to the left in </em><em>quadrants </em><em>2, 1, and 4."</em>
<em />
If you want to learn more about rational functions:
brainly.com/question/1851758
#SPJ1
For (h+g)(x) you just add the two functions:
(h+g)(x) = 4x + 2x^2
For (h•g)(x) you multiply them:
(h•g)(x) = 4x • 2x^2 = 8x^3
For (h-g)(x) you subtract them:
(h-g)(x) = 4x - 2x^2
For (h-g)(-2) you sub -2 into the equation we just created:
(h-g)(-2) = 4(-2) - 2(-2)^2
(h-g)(-2) = -8 - 2(4)
(h-g)(-2) = -8 - 8
(h-g)(-2) = -16