Answer: Active Directory database
Explanation:Active directory database works on ESE (Extensible storage engine) for the functioning.Indexed and sequential access method(ISAM)database persist in the ESE for the management of computer devices.
This functions for providing the quick accessing towards the records through database.The database files contain the data in the ESE indexes and is common to computer information and the user.
Answer:
Computer is an example of electronic device.
Answer:
The answer to this question is given below in the explanation section.
Explanation:
The correct answer to this question is d- 346px.
The complete code of this example is given below:
<div>
style="margin:20px; border:solid 3px #888888;">
</div>
while the image width is 300px.
It is noted that the image width is 300px and the margin is 20 px.
Margin:20px means that image margin from four side is 20 px each.
So the width of dive from both side increase to 40 px and the image has 300 px, then total width becomes 340px. Now the border also has 3px of four sides of the image, then the width of the border becomes 6px.
so the total width of the div tag is 346 px.
In short, we can calculate the width of tag as below:
total width of div= width of image+ width of margin+ width of border
total width of dive= 300px+40px+6px
total width of div=346px.
Solution :
#include
#include
#include
//Converts
to binary string.
* hexadecimal
Binary(char* hexdec)
{
long
= 0;
char *string =
(sizeof(char) * 9);
while (hexdec[i]) {
//Simply assign binary string for each hex char.
switch (hexdec[i]) {
strcat(string, "0000");
break;
strcat(string, "0001");
break;
strcat(string, "0010");
break;
strcat(string, "0011");
break;
strcat(string, "0100");
break;
strcat(string, "0101");
break;
strcat(string, "0110");
break;
strcat(string, "0111");
break;
strcat(string, "1000");
break;
strcat(string, "1001");
break;
case 'A':
case 'a':
strcat(string, "1010");
break;
case 'B':
case 'b':
strcat(string, "1011");
break;
case 'C':
case 'c':
strcat(string, "1100");
break;
case 'D':
case 'd':
strcat(string, "1101");
break;
case 'E':
case 'e':
strcat(string, "1110");
break;
case 'F':
case 'f':
strcat(string, "1111");
break;
default:
printf("\nInvalid hexadecimal digit %c",
hexdec[i]);
string="-1" ;
}
i++;
}
return string;
}
int main()
{ //Take 2 strings
char *str1 =hexadecimalToBinary("FA") ;
char *str2 =hexadecimalToBinary("12") ;
//Input 2 numbers p and n.
int p,n;
scanf("%d",&p);
scanf("%d",&n);
//keep j as length of str2
int j=strlen(str2),i;
//Now replace n digits after p of str1
for(i=0;i<n;i++){
str1[p+i]=str2[j-1-i];
}
//Now, i have used c library strtol
long ans = strtol(str1, NULL, 2);
//print result.
printf("%lx",ans);
return 0;
}