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3 years ago

(Wap) Urgent I need help with this question

Mathematics

1 answer:

Anit [1.1K]3 years ago

5 0

Answer:

12.1

Step-by-step explanation:

In this question, we can use the pythagoras theorem to solve it.

the equation is $\sqrt{11^{2}+5^{2} }$ = slant height.

= 12.1

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I NEED HELP PLS THIS IS DUE IN 3 HOURS

Mariulka [41]

Answer:

Part 1) $x^{2} -2x-2=(x-1-\sqrt{3})(x-1+\sqrt{3})$

Part 2) $x^{2} -6x+4=(x-3-\sqrt{5})(x-3+\sqrt{5})$

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

Part 1)

in this problem we have

$x^{2} -2x-2=0$

$a=1\\b=-2\\c=-2$

substitute in the formula

$x=\frac{-(-2)(+/-)\sqrt{-2^{2}-4(1)(-2)}} {2(1)}\\\\x=\frac{2(+/-)\sqrt{12}} {2}\\\\x=\frac{2(+/-)2\sqrt{3}} {2}\\\\x_1=\frac{2(+)2\sqrt{3}} {2}=1+\sqrt{3}\\\\x_2=\frac{2(-)2\sqrt{3}} {2}=1-\sqrt{3}$

therefore

$x^{2} -2x-2=(x-(1+\sqrt{3}))(x-(1-\sqrt{3}))$

$x^{2} -2x-2=(x-1-\sqrt{3})(x-1+\sqrt{3})$

Part 2)

in this problem we have

$x^{2} -6x+4=0$

$a=1\\b=-6\\c=4$

substitute in the formula

$x=\frac{-(-6)(+/-)\sqrt{-6^{2}-4(1)(4)}} {2(1)}$

$x=\frac{6(+/-)\sqrt{20}} {2}$

$x=\frac{6(+/-)2\sqrt{5}} {2}$

$x_1=\frac{6(+)2\sqrt{5}}{2}=3+\sqrt{5}$

$x_2=\frac{6(-)2\sqrt{5}}{2}=3-\sqrt{5}$

therefore

$x^{2} -6x+4=(x-(3+\sqrt{5}))(x-(3-\sqrt{5}))$

$x^{2} -6x+4=(x-3-\sqrt{5})(x-3+\sqrt{5})$

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3 years ago

Carol, Ann, and Liz each bought a toy fish. Carol's fish is 10 inches longer than Ann's fish. Liz's fish is 2 inches longer than

kykrilka [37]

Ann: 12 inches

Carol: 22 inches

Liz: 24 inches

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3 years ago

Plot the points (5, - 1), (1, - 1) and (- 3, - 1) What the equation of the line that goes through these points?

bearhunter [10]

Answer:

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3 years ago

Read 2 more answers

Please please i need help i will mark u brill

zvonat [6]

Answer:

106 - 8h = 34

Whenever a math question says "when h = 9," they mean you substitute this number where h is in the equation.

106 - 8(9) = 34

106 - 72 = 34

34 = 34

This means the fact that h = 9 is a solution for h.

I hope this helps! I would really appreciate it if you would please mark me brainliest! Have a blessed day!

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