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ss7ja [257]
2 years ago
5

How long did it take for a car to travel 20 meters with a speed of 10m/s

Chemistry
1 answer:
AfilCa [17]2 years ago
6 0

Answer:

2 second

Explanation:

yes

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2. Why is the lonic compound Nacl (table salt) able to dissolve in a glass of the molecular compound water (H20)? (3 points)
melomori [17]

Answer:

The correct answer is C ions from the solute molecules have a strong attraction to the polar solvent molecules.

Explanation:

NaCl or Sodium chloride is an ionic compound which easily get dissolved in polar molecular compound such as water(H2O).

      Both NaCl and H2O are polar compound because the atoms that forms NaCl and H2O have vast difference in their electronegativities.As a result the bonding electrons in both NaCl and H2O are not equally shared.

     NaCl get dissolved in water molecules by dipole dipole interaction.  

6 0
2 years ago
What is the molecular formula of a compound with an empirical formula P2O5 and a gram-molecular mass of 284 grams? And why?
Lana71 [14]
I really don’t know but

Phosphorus pentoxide is a white solid which does not have any distinct odour. The chemical formula of this compound is P4O10. However, it is named after its empirical formula, which is P2O5. The molar mass of phosphorus pentoxide corresponds to 283.9 g/mol.
5 0
2 years ago
Calculate the number of atoms of argon in 75.0 L of argon at STP.<br> ?????
charle [14.2K]
Quero pontos mesmo veu que cu descylapa moçe
5 0
3 years ago
What is some fun facts about the person who started Sand Storms? What can be the worst in a Sand Storms? If you were caught in o
Dahasolnce [82]

Answer:

The clouds that carry the dust can be huge, and miles long. They can rise to be over 305m. They also have wind speeds of at least 40 kilometers.Sandstorms can happen really quickly.

Explanation:

Sandstorms carry with them large volumes of sand and dust. But more than sand, they also carry with them virus spores that interact with the atmosphere. Because of this, I can contact any disease from it.

Other immediate effects of sandstorms to me include the worsening of lung functions if I have asthma. Due to inhalation of large amounts of dust, dust pneumonia could be developed. Diseases such as silicosis could also develop from prolonged exposure to sand. If left untreated, it will eventually lead to asphyxiation and lung cancer. The eyes could also be affected by the particles. Keratoconjunctivitis sicca, or dry eyes, could develop which could lead to blindness. My exposure to sandstorms could have adverse effects on my circulatory system. So I could either die immediately or fall terrible sick it depend on my health issue.

7 0
3 years ago
Suppose a 2.95 g of potassium iodide is dissolved in 350. mL of a 62.0 m M aqueous solution of silver nitrate. Calculate the fin
STALIN [3.7K]

Answer : The final molarity of iodide anion in the solution is 0.0508 M.

Explanation :

First we have to calculate the moles of KI and AgNO_3.

\text{Moles of }KI=\frac{\text{Mass of }KI}{\text{Molar mass of }KI}

Molar mass of KI = 166 g/mole

\text{Moles of }KI=\frac{2.95g}{166g/mole}=0.0178mole

and,

\text{Moles of }AgNO_3=\text{Concentration of }AgNO_3\times \text{Volume of solution}=0.0620M\times 0.350L=0.0217mole

Now we have to calculate the limiting and excess reagent.

The given chemical reaction is:

KI+AgNO_3\rightarrow KNO_3+AgI

From the balanced reaction we conclude that

As, 1 mole of KI react with 1 mole of AgNO_3

So, 0.0178 mole of KI react with 0.0178 mole of AgNO_3

From this we conclude that, AgNO_3 is an excess reagent because the given moles are greater than the required moles and KI is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of AgI

From the reaction, we conclude that

As, 1 mole of KI react to give 1 mole of AgI

So, 0.0178 moles of KI react to give 0.0178 moles of AgI

Thus,

Moles of AgI = Moles of I^- anion = Moles of Ag^+ cation = 0.0178 moles

Now we have to calculate the molarity of iodide anion in the solution.

\text{Concentration of }AgNO_3=\frac{\text{Moles of }AgNO_3}{\text{Volume of solution}}

\text{Concentration of }AgNO_3=\frac{0.0178mol}{0.350L}=0.0508M

Therefore, the final molarity of iodide anion in the solution is 0.0508 M.

3 0
2 years ago
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