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stiv31 [10]
3 years ago
9

HELP NOW WITH EXPONENTS

Mathematics
1 answer:
soldi70 [24.7K]3 years ago
6 0

PLZ MARK BRAINLIEST! :)

Answer:

7^{12}

Step-by-step explanation:

When you divide two numbers that have exponents and have the same base, just subtract the exponents. In this case, 7 is the base of both the dividend and the divisor. So, simply subtract 14 - 2 to get 12. The final answer is 7^{12}.

Hope this helps! :)

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3. triangle abc has angle measures as shown (look at image).
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Answer:

x = 6, ∠B = 50°

Step-by-step explanation:

a) 8x + 2 + 70 + 60 = 180

8x + 132 = 180

8x = 180 - 132 = 48

x = 48/8 = 6

b) ∠B = 180 - 70 - 60 = 50°

or 8x + 2 = 8*6 + 2 = 50°

3 0
2 years ago
A certain virus infects one in every 200 people. a test used to detect the virus in a person is positive 70​% of the time when t
V125BC [204]

We're told that

P(A)=\dfrac1{200}=0.005\implies P(A^C)=0.995

P(B\mid A)=0.7

P(B\mid A^C)=0.05

a. We want to find P(A\mid B). By definition of conditional probability,

P(A\mid B)=\dfrac{P(A\cap B)}{P(B)}

By the law of total probability,

P(B)=P(B\cap A)+P(B\cap A^C)=P(B\mid A)P(A)+P(B\mid A^C)P(A^C)

Then

P(A\mid B)=\dfrac{P(B\mid A)P(A)}{P(B\mid A)P(A)+P(B\mid A^C)P(A^C)}\approx0.0657

(the first equality is Bayes' theorem)

b. We want to find P(A^C\mid B^C).

P(A^C\mid B^C)=\dfrac{P(A^C\cap B^C)}{P(B^C)}=\dfrac{P(B^C\mid A^C)P(A^C)}{1-P(B)}\approx0.9984

since P(B^C\mid A^C)=1-P(B\mid A^C).

4 0
3 years ago
Jenny served one scoop of ice cream to her friends using a 3/4 cup scooper. She
Pepsi [2]

Answer:

75?

Step-by-step explanation:

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      ----

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4 0
3 years ago
Mr. van der westhuizen wants to visit his grandchildren In France. he has heard that it is very expensive for South Africans to
Tomtit [17]

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u got it right

Step-by-step explanation:

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3 years ago
A triangle with vertices at A(0, 0), B(0, 4), and C(6, 0) is dilated to yield a triangle with vertices at A′(0, 0), B′(0, 10), a
Vesnalui [34]

Answer:

2.5

Step-by-step explanation:

A triangle ABC with vertices A(0, 0), B(0, 4), and C(6, 0) is dilated to form a triangle A'B'C' with vertices A′(0, 0), B′(0, 10), and C′(15, 0). If the center of dilation is point A or A' (the origin), then

\dfrac{A'B'}{AB}=\dfrac{A'C'}{AC}.

Since

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then the scale factor of the dilation is

k=\dfrac{10}{4}=\dfrac{15}{6}=2.5.

3 0
3 years ago
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