For this case, the first thing we should do is use the following equation:
f (x) = 200 (1.03) ^ x
We substitute f (x) = 300:
300 = 200 (1.03) ^ x
We clear the value of x:
log1.03 (300/200) = log1.03 ((1.03) ^ x)
x = log1.03 (300/200)
x = 13.72
Answer:
the population will first reach 300 in about 13.72 years.
If I'm correct and the ^ stands for multiplication then the answer should be 5.
The picture is my work just ignore the fraction.
Answer:
the last one 1/6
Step-by-step explanation:
1/2 x 1/3 = 1/6
Answer:
D)The range of f(x) includes values such that y ≥ 1, so the domain of f–1(x) includes values such that x ≥ 1.
Step-by-step explanation:
The missing tables are:
First table
x: 0 1 2
f(x): 1 10 100
Second table
x: 1000 100 10
f^-1(x): 3 2 1
Option A is not correct because f(x) has a y-intercept at (0, 1)
If f(x) has a y-intercept, then f^-1(x) has a x-intercept, which is located at (1, 0). Then option B is not correct
Option C is not correct because the domain of f^-1(x) is associated with x values.
Option D is correct because the domain of f(x) is the range of f^-1(x) and vice versa
