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Eddi Din [679]
3 years ago
14

I need help as soon as possible

Mathematics
1 answer:
UNO [17]3 years ago
5 0

Answer:

Your answer would be

  • (6,2)
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PLEASE HELP ME I NEED HELP FAST
Alexxandr [17]
The answer would be A if i am correct can i get most brainliest

6 0
3 years ago
What is the answer pls?
inna [77]

:) Hope this answers your question :)

6 0
3 years ago
A committee of 15 members is voting on a proposal. Each member casts a yea or nay vote. On a random voting basis, what is the pr
Igoryamba

Answer:

0.006% probability that the final vote count is unanimous.

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they vote yes, or they vote no. The probability of a person voting yes or no is independent of any other person. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Random voting:

So 50% of voting yes, 50% no, so p = 0.5

15 members:

This means that n = 15

What is the probability that the final vote count is unanimous?

Either all vote no(P(X = 0)) or all vote yes(P(X = 15)). So

p = P(X = 0) + P(X = 15)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{15,0}.(0.5)^{0}.(0.5)^{15} = 0.00003

P(X = 15) = C_{15,15}.(0.5)^{15}.(0.5)^{0} = 0.00003

So

p = P(X = 0) + P(X = 15) = 0.00003 + 0.00003 = 0.00006

0.006% probability that the final vote count is unanimous.

7 0
3 years ago
help?! so the question is: a business has $15,000 to spend on airline tickets to travel to a conference. it wants 27 of its empl
egoroff_w [7]
700x + 375(27 - x) = 15000
Solve for x
X=15 business class

Economy class 27-15=12
8 0
4 years ago
Read 2 more answers
Ben uses a compass and a straightedge to bisect angle PQR, as shown below: The figure shows two rays QP and QR having a common e
masha68 [24]

Answer:

∠AQS ≅ ∠BQS when segments AQ and BQ are equal.

Step-by-step explanation:

8 0
3 years ago
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