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Andre45 [30]
3 years ago
9

The diagram shows the distance a tortoise can walk if it walks at a constant pace for 15 minutes. At the same rate, how many kil

ometers can the tortoise walk in 1 hour? Write your answer as a decimal. *
Mathematics
1 answer:
Ber [7]3 years ago
5 0

Answer:

im in middle school and im trying to figure this out as well

Step-by-step explanation:

sorry if i get it i will tell you

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The circumference of a circle is approximately 131.88 centimeters What is the area of the shaded region (6/10 of a circle)
scZoUnD [109]

Answer:

82.97cm^2

Step-by-step explanation:

Given data

Circumference=  131.88 centimeters

We want to find the area of 6/10 part of a circle

Firstly, let us find the area of the circle

We need to get the radius

C= 2πr

131.88= 2*3.142*r

131.88=6.284r

r=  131.88/6.284

r=20.98 cm

Area= πr^2

Area= 3.142*20.98^2

Area= 3.142*440.16

Area= 1382.98cm^2

Hence 6/10 of a 1382.98

=0.06*1382.98

=82.97cm^2

4 0
3 years ago
What point divides directed line segment
Goshia [24]
(22.5,30) it's the ratio
6 0
3 years ago
(X^3+1)dividend (x-1)
bazaltina [42]

x^3=x\cdot x^2 and x^2(x-1)=x^3-x^2. So we have a remainder of

(x^3+1)-(x^3-x^2)=x^2+1

x^2=x\cdot x and x(x-1)=x^2-x. Subtracting this from the previous remainder gives a new remainder

(x^2+1)-(x^2-x)=x+1

x=x\cdot1 and 1(x-1)=x-1. Subtracting this from the previous remainder gives a new one of

(x+1)-(x-1)=2

and we're done since 2 does not divide x. So we have

\dfrac{x^3+1}{x-1}=x^2+x+1+\dfrac2{x-1}

4 0
3 years ago
a hexagon inscribed in a circle has three consecutive sides each of length 3 and three consecutive sides each of length 5. the c
allochka39001 [22]

According to given conditions, m+n is equal to 409.

Consider the diagram below.

In the hexagon ABCDEF, let

AB = BC = CD = 3;

DE = EF = FA = 5;

Arc BAF is equal to one-third of the circle's circumference.

Hence, ∠BCF = ∠BEF = 60°;

Similarly, ∠CBE = ∠CFE = 60°;

Let the point of intersection of BE and CF be P, BE and AD be Q and CF and AD be R.

∴ Δ EFP and Δ BCP are equilateral, and so Δ PQR is also equilateral.

Also, ∠ BAD and ∠ BED subtend the same arc and so do ∠ ABE and ∠ ADE.

∴ Δ ABQ is similar to Δ EDQ

\frac{AQ}{EQ}  = \frac{BQ}{DQ} = \frac{AB}{ED} = \frac{3}{5}

Also,

\frac{\frac{AD - PQ}{2} }{PQ + 5} = \frac{3}{5}  

and \frac{3 - PQ}{\frac{AD + PQ}{2} }  = \frac{3}{5}

On solving these simultaneous equations, we get AD = 360/49

∴ m + n = 409.

To learn more about similarity of triangles, refer to this link:

brainly.com/question/25882965

#SPJ4

4 0
1 year ago
Yesterday, Brian had 97 baseball cards. Today, he got more. Using
Ket [755]

Answer:

97+x

Step-by-step explanation:

Let x represent how many cards he got.

3 0
3 years ago
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