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50 POINTS what is the average rate of change of the function f(x)=3x^2 on the interval from 0 to 2?

Evgesh-ka [11]

Answer:

f=3x-2

Step-by-step explanation:

5 0

3 years ago

What would be the equation to you have a part time job. You work for 3h on Friday and 6h on Saturday. You also recieve an allowa

HACTEHA [7]

Answer:

Step-by-step explanation:

So, to go about your question, we must first ask, how many hours a week is being worked?

In this problem, that is 9 hours per week.

Next, we must question how much per week is made

That is $92 per week

Finally, we must determine if the allowance is occuring many times in the week or just once.

In this problem, that is only occuring once for the week.

So, the equation we must setup is 9x +20 =92.

To solve the equation, we need to subtract 20 on both sides to isolate the variable, x.

9x+20=92

-20 -20

Now our equation is

9x=72

Now, to finally get x by itself or to isolate x, you should divide 9 on both sides to cancel out the 9 being multiplied by the x.

9x=72

9 9

x=8 because of 72/9 is equal to 8.

I hope this helps, and I will answer any questions you have.

5 0

3 years ago

(2pm^-1q^0)^-4 • 2m ^-1 p^3 / 2pq^2

Montano1993 [528]

Answer:

$\dfrac{m^3}{16p^2q^2}$

Step-by-step explanation:

Given:

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}$

1.

$m^{-1}=\dfrac{1}{m}$

2.

$q^0=1$

3.

$2pm^{-1}q^0=2p\cdot \dfrac{1}{m}\cdot 1=\dfrac{2p}{m}$

4.

$(2pm^{-1}q^0)^{-4}=\left(\dfrac{2p}{m}\right)^{-4}=\left(\dfrac{m}{2p}\right)^4=\dfrac{m^4}{(2p)^4}=\dfrac{m^4}{16p^4}$

5.

$m^{-1}=\dfrac{1}{m}$

6.

$2m^{-1} p^3=2\cdot \dfrac{1}{m}\cdot p^3=\dfrac{2p^3}{m}$

7.

$\dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{\frac{2p^3}{m}}{2pq^2}=\dfrac{2p^3}{m}\cdot \dfrac{1}{2pq^2}=\dfrac{p^2}{mq^2}$

8.

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}$

8 0

3 years ago

Find an equation of the line passing through the pair of points. Write the equation in the form Ax +By = C.

Alexxandr [17]

9514 1404 393

Answer:

5x -y = -37

Step-by-step explanation:

One way to find the coefficients A and B is to use the differences of the x- and y-coordinates:

A = Δy = y2 -y1 = 2 -(-3) = 5

B = -Δx = -(x2 -x1) = -(-7 -(-8)) = -1

Then the constant C can be found using either point.

5x -y = 5(-7) -2 = -37

The equation of the line is ...

5x -y = -37

_____

Additional comment

This approach comes from the fact that the slope of a line is the same everywhere.

$\dfrac{y-y_1}{x-x_1}=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{\Delta y}{\Delta x}\\\\\Delta x(y-y_1)=\Delta y(x-x_1)\qquad\text{cross multiply}\\\\\Delta y(x-x_1)-\Delta x(y-y_1)=0\qquad\text{subtract y term}\\\\\Delta y(x) -\Delta x(y) = \Delta y(x_1)-\Delta x(y_1)\qquad\text{Ax+By=C form}$

The "standard form" requires that A be positive, so we chose point 1 and point 2 to make sure that was the case.

5 0

2 years ago

Using the following triangle, what is the cosine of angle B?

stealth61 [152]

Hello!

To find cosine, use the formula cos = adjacent / hypotenuse.

According to angle B, adjacent of angle B is side A, and the hypotenuse is side c because the hypotenuse is always opposite the right angle.

Therefore, the cosine of angle B is a/c.

3 0

3 years ago