Given :
Kareem heats a beaker of water to boil. Then he records that the water temperature decreases from 100° C to 19° C in 5 2/5 minutes.
To Find :
What was the charged in temperature each minute.
Solution :
Time taken to reach 19° C :
Now, change in temperature per minute is given by :
Therefore, the charged in temperature each minute is -15 °C/minute .
Hence, this is the required solution.
Answer:
1 and 36/45
Step-by-step explanation:
First, you have to make the denominators the same so that you can add them.
The smallest number that both 15 and 9 are factors of is 45.
Since you had to multiply 15 by 3 to get 45, you need to multiply 7 by 3 as well. this leaves with the fraction 1 21/45.
You multiplied 9 by 5 to get 45 so now you need to multiply 3 by 5 as well leaving you with the fraction 15/45.
Now all you have to do is add 1 21/45 + 15/45.
15 + 21 = 36 leaving you with your answer:
1 36/45
Hope this helps!
Answer:
As you know, g = 9.81 m/s on the surface of the Earth. ... If the action force is the force she exerts downward on the chair, what is the reaction force? ... it take a 10-N force to increase the speed of a 10-kg toy car from 1.00 m/s to 4.00 m/s? ... (DH 32) How many joules of kinetic energy does a .5 kg cart have when it is ...
Step-by-step explanation:
Answer:
x = - 39/148
y = -6/37
Step-by-step explanation:
substitute the given value of y into the equation to get 8x-13 (12x+3)=0
solve for x to get x= - 39/148
substitute the given value of x into 12x+3=y
12 x (-39/148) + 3 = y
-6/37 = y
40 questions. You set up a proportion, mutiply 34 by a 100 and get 3400. Then you divide 3400 by 85 and you get ur answer. You could also try guessing by putting in random values you think are the whole number and multiplying them by 0.85. So if you guess 44 is the whole and try checking it by multiplying it by .85 and get a value thats higher than the value the percentage is equal to you try another smaller value. So if 44 doesn't work you can try 40. 40 times .85 is 34 so your answer of 40 questions is correct.
