Question

4. Write the equation of the line that is parallel to the line y=-3x+4 that goes

Answer 1

Answer:

Y = $\frac{X}{3} - 9$

Step-by-step explanation:

Given equation of first line as

Y = -3X + 4

Slop of the first line (m1) = -3

As first line is parallel to second line , then (m1) × (m2) = - 1

i.e m2 = $\frac{-1}{m1}$

m2 = $\frac{-1}{-3}$

m2 = $\frac{1}{3}$

Now equation of seconf line with points (9 , -6) and slop $\frac{1}{3}$

i.e equation of new line Y - y1 = m2 (X - x1)

                                       Y + 6= $\frac{1}{3}$

Y = $\frac{X}{3} - \frac{9}{3} - 6$

Hence equation of new line is

Y = $\frac{X}{3} - 9$    Answer