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Rainbow [258]
3 years ago
12

What is the slope of the line?

Mathematics
1 answer:
meriva3 years ago
7 0
The slope of the line can be defined as y = mx + b, where m is the slope
To find the slope, one will need to use the expression Δy/Δx (y final - y initial)/(x final - x initial)
For this problem, that equals 1/3

Now we will use the point slope form
(y - y initial) = m (x - x initial):

y + 1 = 1/3 (x - 2)

y = 1/3x - 5/3
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How much interest is earned on a principal of 646 invested at an interest rate of 5 for two years
IceJOKER [234]

Answer:

Step-by-step explanation:

P=646

R=5%

T=2yrs

I=?

I=PRT/100

I= 646*5*2/100

I= 64.6

5 0
3 years ago
Do you notice clusters or outliners in the data ? Explain your reasoning
Kay [80]
Yes,I do 1,110 is a cluster because it’s a very large number for 52 degrees and 189 is because it’s a very large number for 16 degrees.


Hope this helps :)
4 0
3 years ago
Consider the table of the powers of 8.
allsm [11]
A= 0
B= -8
C= -64

I learned how to do math and that is correct
6 0
3 years ago
Read 2 more answers
What is the area of the
makvit [3.9K]

Answer:

D. 720cm squared is the answer

8 0
3 years ago
A store selling newspapers orders only n = 4 of a certain newspaper because the manager does not get many calls for that publica
umka2103 [35]

Answer:

a) The expected value is 2.680642

b) The minimun number of newspapers the manager should order is 6.

Step-by-step explanation:

a) Lets call X the demanded amount of newspapers demanded, and Y the amount of newspapers sold. Note that 4 newspapers are sold when at least four newspaper are demanded, but it can be <em>more</em> than that.

X is a random variable of Poisson distribution with mean \mu = 3 , and Y is a random variable with range {0, 1, 2, 3, 4}, with the following values

  • PY(k) = PX(k) = ε^(-3)*(3^k)/k! for k in {0,1,2,3}
  • PY(4) = 1 -PX(0) - PX(1) - PX(2) - PX (3)

we obtain:

PY(0) = ε^(-3) = 0.04978..

PY(1) = ε^(-3)*3^1/1! = 3*ε^(-3) = 0.14936

PY(2) = ε^(-3)*3^2/2! = 4.5*ε^(-3) = 0.22404

PY(3) = ε^(-3)*3^3/3! = 4.5*ε^(-3) = 0.22404

PY(4) = 1- (ε^(-3)*(1+3+4.5+4.5)) = 0.352768

E(Y) = 0*PY(0)+1*PY(1)+2*PY(2)+3*PY(3)+4*PY(4) =  0.14936 + 2*0.22404 + 3*0.22404+4*0.352768 = 2.680642

The store is <em>expected</em> to sell 2.680642 newspapers

b) The minimun number can be obtained by applying the cummulative distribution function of X until it reaches a value higher than 0.95. If we order that many newspapers, the probability to have a number of requests not higher than that value is more 0.95, therefore the probability to have more than that amount will be less than 0.05

we know that FX(3) = PX(0)+PX(1)+PX(2)+PX(3) = 0.04978+0.14936+0.22404+0.22404 = 0.647231

FX(4) = FX(3) + PX(4) = 0.647231+ε^(-3)*3^4/4! = 0.815262

FX(5) = 0.815262+ε^(-3)*3^5/5! = 0.91608

FX(6) = 0.91608+ε^(-3)*3^6/6! = 0.966489

So, if we ask for 6 newspapers, the probability of receiving at least 6 calls is 0.966489, and the probability to receive more calls than available newspapers will be less than 0.05.

I hope this helped you!

8 0
3 years ago
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