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rewona [7]
2 years ago
9

Which equation represents a circle that contains the point (–5, –3) and has a center at (–2, 1)?

Mathematics
2 answers:
Zinaida [17]2 years ago
6 0

Answer:

C

Step-by-step explanation:

for us lazy folks.

melisa1 [442]2 years ago
3 0

Answer:

(x + 2)² + (y - 1)² = 25

Step-by-step explanation:

radius: r² = (1 - (-3))² + (-2 - (-5))² = 16 + 9 = 25

r = 5

Circle: (x - h)² + (y - k)² = r²

center: (-2 , 1)      h = -2       k = 1

(x + 2)² + (y - 1)² = 25

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Find the value of k by<br>quardractic equation two real and equal roots<br>5x - 2kx +20=0​
kotegsom [21]

Answer:

k = +10 or -10

Step-by-step explanation:

It's given in the question that the roots of the eqn. are real and equal. So , the discriminant of the eqn. should be equal to 0.

=  >  {b}^{2}  - 4ac = 0

=  >  {( - 2k)}^{2}  - 4 \times 5 \times 20 = 0

=  > 4 {k}^{2}  - 400 = 0

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3 0
2 years ago
Read 2 more answers
Tickets for seniors prom cost $25 for individual tickets and $40 for couples tickets. They collected a total of 2500 from ticket
quester [9]

Answer: 20

Step-by-step explanation:

Given

The cost of an individual ticket is $25

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total ticket sold is 70

Suppose there are x individuals and y couples

\therefore x+y=70\quad \ldots(i)\\\\25x+40y=2500\quad \ldots(ii)\\\text{Solving }(i)\ \text{and}\ (ii)\ \text{we get}

x=20,y=50

So, they sold 20 tickets of the individual.

8 0
3 years ago
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