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IrinaVladis [17]
3 years ago
15

Helpppp plzzzzzzzzzz

Mathematics
1 answer:
tamaranim1 [39]3 years ago
6 0

Given:

Two numbers are 32 and 28.

To find:

The GCF of 32 and 28 and using the GCF find the factor of (32-28).

Solution:

(a)

Two numbers are 32 and 28. The factor form of given numbers are:

32=2\times 2\times 2\times 2\times 2  

28=2\times 2\times 7

Clearly, 2 and 2 are common factors in both.

GCF(32,28)=2\times 2

GCF(32,28)=4

Therefore, the GCF of 32 and 28 is 4.

(b)

Using the GCF we need to find the factor of (32-28).

32-28=4\times 8-4\times 7

Taking out the GCF, we get

32-28=4\times (8-7)

Therefore, 32-28=4\times (8-7).

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The U.S. Bureau of Economic Statistics reports that the average annual salary in the metropolitan Boston area is $50,542. Suppos
xenn [34]

Answer:

(a) P(X > $57,000) = 0.0643

(b) P(X < $46,000) = 0.1423

(c) P(X > $40,000) = 0.0066

(d) P($45,000 < X < $54,000) = 0.6959

Step-by-step explanation:

We are given that U.S. Bureau of Economic Statistics reports that the average annual salary in the metropolitan Boston area is $50,542.

Suppose annual salaries in the metropolitan Boston area are normally distributed with a standard deviation of $4,246.

<em>Let X = annual salaries in the metropolitan Boston area</em>

SO, X ~ Normal(\mu=$50,542,\sigma^{2} = $4,246^{2})

The z-score probability distribution for normal distribution is given by;

                      Z  =  \frac{X-\mu}{\sigma }  ~ N(0,1)

where, \mu = average annual salary in the Boston area = $50,542

            \sigma = standard deviation = $4,246

(a) Probability that the worker’s annual salary is more than $57,000 is given by = P(X > $57,000)

    P(X > $57,000) = P( \frac{X-\mu}{\sigma } > \frac{57,000-50,542}{4,246 } ) = P(Z > 1.52) = 1 - P(Z \leq 1.52)

                                                                     = 1 - 0.93574 = <u>0.0643</u>

<em>The above probability is calculated by looking at the value of x = 1.52 in the z table which gave an area of 0.93574</em>.

(b) Probability that the worker’s annual salary is less than $46,000 is given by = P(X < $46,000)

    P(X < $46,000) = P( \frac{X-\mu}{\sigma } < \frac{46,000-50,542}{4,246 } ) = P(Z < -1.07) = 1 - P(Z \leq 1.07)

                                                                     = 1 - 0.85769 = <u>0.1423</u>

<em>The above probability is calculated by looking at the value of x = 1.07 in the z table which gave an area of 0.85769</em>.

(c) Probability that the worker’s annual salary is more than $40,000 is given by = P(X > $40,000)

    P(X > $40,000) = P( \frac{X-\mu}{\sigma } > \frac{40,000-50,542}{4,246 } ) = P(Z > -2.48) = P(Z < 2.48)

                                                                     = 1 - 0.99343 = <u>0.0066</u>

<em>The above probability is calculated by looking at the value of x = 2.48 in the z table which gave an area of 0.99343</em>.

(d) Probability that the worker’s annual salary is between $45,000 and $54,000 is given by = P($45,000 < X < $54,000)

    P($45,000 < X < $54,000) = P(X < $54,000) - P(X \leq $45,000)

    P(X < $54,000) = P( \frac{X-\mu}{\sigma } < \frac{54,000-50,542}{4,246 } ) = P(Z < 0.81) = 0.79103

    P(X \leq $45,000) = P( \frac{X-\mu}{\sigma } \leq \frac{45,000-50,542}{4,246 } ) = P(Z \leq -1.31) = 1 - P(Z < 1.31)

                                                                      = 1 - 0.90490 = 0.0951

<em>The above probability is calculated by looking at the value of x = 0.81 and x = 1.31 in the z table which gave an area of 0.79103 and 0.9049 respectively</em>.

Therefore, P($45,000 < X < $54,000) = 0.79103 - 0.0951 = <u>0.6959</u>

3 0
3 years ago
If the price of 1 dozens of apples is Rs 84, find the price of 4 apples.​
Alexxx [7]

Answer:

The price of 4 apples is Rs 28

Step-by-step explanation:

The price of 1 dozen apple is Rs 84

12 apples =Rs 84

1 apple = Rs 84÷12

1apple =Rs 7

Again

Price of 4 apples = Rs 7 × 4

= Rs 28 Ans,,

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3 years ago
If g(x)=7x²−4x−3 and h(x)=5x²−12x, find (h∘g)(1)<br><br><br>FIRST BEST ANSWER BRAINLIEST
AURORKA [14]

Answer: See below

Step-by-step explanation:

h\:\circ \:g=h\left(g\left(x\right)\right)

=5\left(7x^2-4x-3\right)^2-12\left(7x^2-4x-3\right)

=5\left(7x^2-4x-3\right)\left(7x^2-4x-3\right)-12\left(7x^2-4x-3\right)

=245x^4-280x^3-130x^2+120x+45-84x^2+48x+36

Simplify:

=245x^4-280x^3-214x^2+168x+81

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−16t2+75 Solve for t=2
SVETLANKA909090 [29]

Answer:

=−16t^2+75

Step-by-step explanation:

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Answer:

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