1 answer:
Answer:
12
Step-by-step explanation:
Let's put the equations in standard form. For the first equation, we have:
−11y=6(z+1)-13y
2y−6z=6
y−3z=3
The second equation is:
4y−24=c(z−1)
4y−cz=24−c
If we multiply the first equation by 4, we get:
4y-12z=12
Comparing the two equations, we see that if c=12, both equations will be the same and there will be infinitely many solutions.
The correct value of c is 12.
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