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3 years ago

What is the length of the hypotenuse?

Mathematics

2 answers:

PIT_PIT [208]3 years ago

3 0

Answer:

Hello! answer: 68

Step-by-step explanation:

Hello I explained how to find the answer already for you so I will just show the work here

60 × 60 = 3600

32 × 32 = 1024

3600 + 1024 = 4624

√4624 = 68

68 × 68 = 4624 therefore c = 68 Hope that helps!

romanna [79]3 years ago

3 0

Answer:

c= 68

Step-by-step explanation:

$a^{2} + b^{2} = c^{2}$

$32^{2} + 60^{2}= c^{2}$

$4624= c^{2}$

$\sqrt{4624} = c$

68 = c

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Read 2 more answers

V= 512^2/3* 19683^1/3*256^1/4

irina1246 [14]

Answer:

V=512^2/3* 19683^1/3*256^1/4 = 6912

Step-by-step explanation:

V= $(512^{\frac{2}{3} } ) \times (19683^{\frac{1}{3} } )\times (256^{\frac{1}{4} } )\\$

$2^{9} = 512\\2^{8} = 256\\19683^{\frac{1}{3} } = 27\\$

putting values in equation

V= $2^{9(^{\frac{2}{3} } )} \times 27 \times 2^{8^({\frac{1}{4}) } } \\$ let it be equation 1

$2^9^{\frac{2}{3} } = 2^6 according\,to\,exponential\,rule\\2^8^\frac{1}{4} = 2^2 according\,to\,exponential\,rule\\\\$

putting values in equation 1

$V= 2^6\times 27\times 2^2$

According to exponential rule $2^6 \times 2^2 = 2^8$

V= $2^8 \times 27\\$

$V=256\times 27\\V=6912$

V= 6912

Keywords: Algebra

Learn more about algebra at:

#learnwithBrainly

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3 years ago