The equation which models the distance (d) of the weight from its equilibrium after time (t) is equal to d = -9cos(2π/3)t.
<h3>What is the period of a cosine function?</h3>
The period of a cosine function simply means the total length (distance) of the interval of values on the x-axis over which a graph lies and it's repeated.
Since the weight attached is at its lowest point at time (t = 0), therefore, the amplitude of equation will be negative nine (-9)
For the angular velocity at time period (t = 3s), we have:
ω = 2π/T
ω = 2π/3
Mathematically, the standard equation of a cosine function is given by:
y = Acos(ω)t
Substituting the given parameters into the formula, we have;
d = -9cos(2π/3)t.
Read more on cosine function here: brainly.com/question/4599903
IF you are solving for d:
isolate the D, do the opposite of PEMDAS.
-d/6 + 12 = -7
(subtract 12 from both sides)
-d/6 + 12 (-12) = -7 (-12)
-d/6 = -19
(multiply 6 to both sides)
-d/6(6) = -19(6)
-d = -19(6)
-d = -144
-d/-1 = -144/-1
d = 144
hope this helps
Answer:
D
Step-by-step explanation:
Geometric sequence has to do with a pattern of multiplication, and D has a pattern of times 4 if that makes any sense
1000*(1.06)^8. I'm lazy and don't want to type this into a calculator, but what you get out is the answer.
Answer:
x^3 -9x^2 +14x +24
Step-by-step explanation:
(x-4)(x^2 - 5x - 6)
Multiply the x by everything in the second term
x * (x^2 - 5x - 6)
x^3 -5x^2 -6x
Multiply the -4 by everything in the second term
-4 * (x^2 - 5x - 6)
-4x^2 +20x +24
Add everything together
I like to line them up vertically
x^3 -5x^2 -6x
-4x^2 +20x +24
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x^3 -9x^2 +14x +24
