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MrRa [10]
3 years ago
8

The total profit for a company in February was 15% higher than it was in January. The total profit for the two months was $122,9

80. Find the profit for January
Mathematics
1 answer:
stepladder [879]3 years ago
7 0

Answer:

The profit for January is $57,200.

Step-by-step explanation:

The total profit for the two months would be the result of adding up the profit in January plus the profit in February:

Total profits=Profit in January+Profit in February

Also, you can say that profits in January can be represented by x and you know that the profit for a company in February was 15% higher than it was in January which can be expressed as: 1.15x. Moreover, you know that the total profit for the two months was $122,980. Now, you can replace the values on the formula:

122,980=x+1.15x

Now, you can solve for x:

122,980=2.15x

x=122,980/2.15

x=57,200

According to this, the answer is that the profit for January is $57,200.

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Which expression has a value of 1/36?
Nataly [62]

Answer:

1/36) = 0.0277777777778

(1/108)^3 = 7.9383224102 x 10^-7

(1/9)^4 = 0.000152415790276

(1/6)^2 = 0.0277777777778

(1/2)^5 = 0.03125

The only one that matches with the value of 1/36 is (1/6)^2. Therefore, your answer is . (1/6)^2

8 0
2 years ago
The savings account offering which of these APRs and compounding periods offers the best APY?
zzz [600]
\bf \qquad  \qquad  \textit{Annual Yield Formula}
\\\\
~~~~~~~~~~~~\textit{4.0784\% compounded monthly}\\\\
~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0784\%\to \frac{4.0784}{100}\to &0.040784\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
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\end{array}\to &12
\end{cases}
\\\\\\
\left(1+\frac{0.040784}{12}\right)^{12}-1\\\\
-------------------------------\\\\
~~~~~~~~~~~~\textit{4.0798\% compounded semiannually}\\\\


\bf ~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0798\%\to \frac{4.0798}{100}\to &0.040798\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, thus twice}
\end{array}\to &2
\end{cases}
\\\\\\
\left(1+\frac{0.040798}{2}\right)^{2}-1\\\\
-------------------------------\\\\


\bf ~~~~~~~~~~~~\textit{4.0730\% compounded daily}\\\\
~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
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n=
\begin{array}{llll}
\textit{times it compounds per year}\\
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7 0
3 years ago
Read 2 more answers
Plz help i am confusion
kari74 [83]

Answer:

NO solution , the -17y at both sides will cancel ,so no variable left

Step-by-step explanation:

3 0
3 years ago
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Solve the following equation:<br> a) 3x - 9 = 27/ 1 - 5x<br> b) 10x - 1/x = 3
mars1129 [50]

Answer:

A) x=9/2 B) x=-1/5, 1/2

Step-by-step explanation:

3x-9=27/1-5x

3x-9=27-5x

3x-(-5x)-9=27

3x+5x-9=27

8x-9=27

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8x=36

x=36/8

simplify

x=9/2

Answer: x=9/2

-----------------------------

10x-1/x=3

(10x^2-1)/x=3

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10x^2-1=3x

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factor out the trinomial,

find two numbers that when they multiply,

you get the third term, which is -1 in this case.

When you add those 2 numbers, you get the second term,

which is -3 in this case.

(5x+1)(2x-1)=0

apply the zero property from here,

set 5x+1=0 and 2x-1=0 and solve for x.

5x=0-1=-1, x=-1/5,

2x=0+1=1, 2x=1, x=1/2.

So x=-1/5, 1/2.

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