x²+y²-2x-6y-5=0
x²-2x+y²-6y=5
x²-2x+1+y²-6y+9=5+1+9
(x-1)²+(y-3)²=15
(x-1)²+(y-3)²=(V15)²
-> centre of the circle: C(-1,-3)
-> radius of the circle: V15
Answer:
C. Quadrant III
Step-by-step explanation:
All good and for number 6 you should draw an acute angle
The numbers that have a digit in the ones place that is 1/10 of the value in the tens place are 1,055 and 3,222.
<h3>What digits are in the ones place?</h3>
The ones place refers to the position immediately before the decimal.
The digit in the tens place is the number immediately left of the ones place.
The numbers that have ones digits that are 1/10 of the digits in the tens place that are 1,055 and 3,222.
That is because 5 is 1/10 of the tens value of 50 and 2 is 1/10 of the 20 in the tens place.
Find out more on the positions of digits at brainly.com/question/579274
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19, 12, 3, 6, 18, 20, 4, 4, 8, 12, 16, 20, 10, 1, 7, 8 1. Find the range of the data
german
Answer:
The highest observation =20
The lowest observation = 1
Range of the data = 20-1
= 19(ans)
