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3 years ago

Suppose that a phone that originally sold for $800 loses 3/5 of its value each year after it is released.

Mathematics

1 answer:

liubo4ka [24]3 years ago

3 0

Answer:

It will be worth $128.

Step-by-step explanation:

After 1 year, 3/5 of 800 is 480 which leaves the value at $320, and then after 2 years, 3/5 of 320 is 192. 320-192 leaves the value at $128.

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3 years ago

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3 years ago

MULTIPLE CHOICE HELP ASAP! Brainliest for correct answer.

N76 [4]

Answer:

An equation of the circle with centre (-2,1) and radius 3 is $\mathbf{(x+2)^2+(x-1)^2=9}$

Option D is correct.

Step-by-step explanation:

Looking at the figure we get centre of circle C (-2,1) and radius of circle r = 3

The equation of circle is of form: $(x-h)^2+(x-k)^2=r^2$ where (h,k) is centre and r is radius.

We have centre C (-2,1) so, we have h = -2 and k = 1

We have radius = 3 so, r = 3

Putting values in the equation and finding the required equation:

$(x-h)^2+(x-k)^2=r^2\\(x-(-2))^2+(x-1)^2=(3)^2\\(x+2)^2+(x-1)^2=9$

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Option D is correct.

7 0

2 years ago

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Gekata [30.6K]

Answer:

Step-by-step explanation:

$\frac{3 }{27} \frac{miles}{minutes}$ * $\frac{60}{1} \frac{min}{hour}$ * $\frac{1}{.6213} \frac{km}{mile}$

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3 years ago

Which set is closed under subtractionWhich answer choice shows that the set of irrational numbers is not closed under addition

vovikov84 [41]

Answer:

(a) Set of rational numbers

(b) $\pi + (-\pi) = 0$

Step-by-step explanation:

Solving (a): Set that is closed under subtraction

The solution to this is rational numbers.

For a set of number to be closed under subtraction, the following condition must be true

$a -b = c$

Where

a, b, c are of the same set.

The above is only true for rational numbers.

e.g.

$1 - 2 = -1$

$5 - 5 = 0$

$\frac{1}{2} - \frac{1}{4} = \frac{1}{2}$

$4 - 2 = 2$

The operations and the result in the above samples are rational numbers.

Solving (b): Choice not close under addition[See attachment for options]

As stated in (a)

For a set of number to be closed under subtraction, the following condition must be true

$a -b = c$

Where

a, b, c are of the same set.

In the given options (a) to (d), only

$\pi + (-\pi) = 0$ is not close under addition because:

$\pi$ is irrational while $0$ is rational

<em>In other words, they belong to different set</em>

8 0

2 years ago