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3 years ago

unit 10: circles Homework 4: Inscribed angles. please complete the following questions and explain how it is done.

Mathematics

1 answer:

tangare [24]3 years ago

3 0

Answer:

Step-by-step explanation:

5. angle FDE = 180-90-63 = 27°

arc FE = 2×27 = 54°

6. arc GJ = 360-68-31-115 = 146°

angle GHJ = 146/2 = 73°

7. angle GIJ = 146/2 = 73°

8. arc DAB = 2×101 = 202°

arc BCD = 360°-202 = 158°

angle A = 158/2 = 79°

angle B = 360-79-110-68 = 112°

10. see picture

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How do you write 4 1/3 : 7 in simplest form

Tema [17]

4 1/3:7 can be written in many ways
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Hope this helps! ;)

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3 years ago

A fishbowl shaped like a sphere is filled with water. The fishbowl has a diameter of 16 inches. Which measurement is closet to t

rjkz [21]

Answer:

A) 2144.66 in³

Step-by-step explanation:

A fishbowl shaped like a sphere is filled with water. The fishbowl has a diameter of 16 inches. Which measurement is closet to the volume of water in the fishbowl in cubic inches?

Volume of a sphere = 4/3πr³

Diameter = 16 in

Radius = Diameter/2 = 16 in/2 = 8 in

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= 2144.66 cubic Inches

Option A.is correct

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3 years ago

Help me with this question please ? and how do I get the answer?

melamori03 [73]

1) you have to find the difference between pipe A and pipe B, which is 6.40.

23.55-17.15=6.40

2) after finding the difference. You will take that difference and put it out of 23.55 and multiply by 100 to get your percentage. As so:

(6.40/23.55)(100)= 27.176% which rounds to 27% as a whole number.

Your answer is 27%. Hope that helps!

7 0

3 years ago

.........................................................................

vlabodo [156]

Answer:

Thanks for the free points.

Step-by-step explanation:

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3 years ago

7 measured data points have a sample mean of 1403 and a standard deviation of 27. Determine the best estimate of the mean value

mina [271]

Answer:

Step-by-step explanation:

Hello!

You have sample of n=7 with mean X[bar]= 1403 and standard deviation S=27 and are required to estimate the mean with a 95%CI.

Asuming this sample comes from a normal population I'll use a stuent t to estimate the interval (a sample of 7 units is too small for the standard normal to be accurate for the estimation):

[X[bar]± $t_{n-1;1-\alpha /2}$ * $\frac{S}{\sqrt{n} }$ ]

$t_{n-1;1-\alpha /2} = t_{6;0.975}= 2.365$

[1403±2.365* $\frac{27}{\sqrt{7} }$ ]

[1378.87;1427.13]

The margin of error is the semiamplitude of the interval and you can calculate it as:

$d= \frac{Upbond-Lowbond}{2}= \frac{1427.13-1378.87}{2} = 24.13$

With a confidence level of 95% you'd expect that the real value of the mean is contained by the interval [1378.87;1427.13], the best estimate of the mean value is expected to be ± 24.13 of 1403.

I hope it helps!

4 0

3 years ago

unit 10: circles Homework 4: Inscribed angles. please complete the following questions and explain how it is done. ​

unit 10: circles Homework 4: Inscribed angles. please complete the following questions and explain how it is done.