First, we always have to list them from least to greatest: 3,7,10,11,12,14,15,17,17,21.
A. I attached an image of the cumulative frequency table.
B. I wasn't able to make a histogram since I can't find any templates or programs to create it on.
Part C:
Mean: 12.7
Median: 26/2=13
Mode: 17
Range: 21 -3 = 18
Part D:
Minimum: 3
First Quartile: 10
Third Quartile: 17
Maximum: 21
E. I can't a program again, but I can help you over a call if you'd wish.
Part F:
40th Percentile: 0.31
Given:
The sets are
and
.
To find:
Whether A and B are disjoint sets or not.
Solution:
Two sets are called disjoint sets if there are no common elements between them.
We have,
![A=\{1,3,5,6\}](https://tex.z-dn.net/?f=A%3D%5C%7B1%2C3%2C5%2C6%5C%7D)
![B=\{0,7\}](https://tex.z-dn.net/?f=B%3D%5C%7B0%2C7%5C%7D)
Clearly, there is not common elements between the set A and set B.
Therefore, the sets A and B are disjoint sets.
Good morning ☕️
Answer:
![r < \frac{4}{7}](https://tex.z-dn.net/?f=r%20%3C%20%5Cfrac%7B4%7D%7B7%7D)
Step-by-step explanation:
35r-21 < -35r+19
⇌ 35r + 35r < 19 + 21
⇌ 70r < 40
⇌ r < 40/70
⇌ r < 4/7
_________________________
:)
Answer:
The missing side is 9cm.
How I got my answer:
1. Squares have equal sides.
2. The area is 81cm^2, so we have to divide 81 by 9.
81 : 9 = 9cm.
Answer:
a) 121,000
b)8.35 x 10^-6
Step-by-step explanation: