Write the equation of the line that passes through (1, -2) and is parallel to x - 2y = -2.
1 answer:
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Alrigty
in form
the vertex is (h,k)
the constant, a, deterimines the size and direction
if a>0, then the parabola opens up and the vertex is the minimum
if a<0 then the parabola opens down and the vertex is the maximum
so we are given
1>0 so it opens up
vertex is (-2,4)
the vertex is a minimum
the vertex is (-2,4) and the graph has a minimum
in form
the vertex is (h,k)
the constant, a, deterimines the size and direction
if a>0, then the parabola opens up and the vertex is the minimum
if a<0 then the parabola opens down and the vertex is the maximum
so we are given
1>0 so it opens up
vertex is (-2,4)
the vertex is a minimum
the vertex is (-2,4) and the graph has a minimum
Step-by-step explanation:
<h3>Answer:-</h3>Here, Unitary Method is used. It tells:-
$
$
$ is the answer.
Hope it helps :D