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GuDViN [60]
3 years ago
14

The quantum mechanical model of the hydrogen atom requires that if the orbital quantum number of the hydrogen atom is 4, there w

ill be how many permitted orbital magnetic quantum numbers will be:_______
Physics
1 answer:
stich3 [128]3 years ago
4 0

Answer:

-4, -3, -2, -1, 0, 1, 2, 3, 4  

Explanation:

There are four sets of quantum numbers;

1) principal quantum number (n)

2)orbital quantum number (l)

3) magnetic quantum number (ml)

4) Spin quantum number (s)

These quantum numbers describes the probability of finding the electron within the atom.

The values of the magnetic quantum number depends on the orbital quantum number. The range of values of the magnetic quantum number is -l to +l

Hence, if the orbital quantum number of the hydrogen atom is 4, the permitted orbital magnetic quantum numbers will be; -4, -3, -2, -1, 0, 1, 2, 3, 4.  

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A bucket filled woth water seems light while it sinks into water.Also show their relation using formula
slavikrds [6]

Answer: This phenomenon happens due to upthrust exerted by water.

Explanation:

We know that,

Liquid Pressure is directly proportional to the height of the vertical column in the liquid.(P∝h)

When a bucket filled water is sunk into the water container, there occur difference in the pressure in top and bottom of the water container. Due to this, water exerts an upward force on the bucket filled with water. This is called Uprthrust.

Upthrust on the bucket makes the bucket filled with water lose some of it's weight and causes apparent loss in weight.

Hence, the bucket filled with water seems light while it sinks into water.

6 0
3 years ago
You are working in a shoe test laboratory measuring the coefficients of friction for running shoes on a variety of surfaces. The
AnnZ [28]

Answer:

0.75

Explanation:

Since the static frictional force is the maximum force applied just before sliding, our frictional force, F is 300 N.

Since F = μN where μ = coefficient of static friction and N = normal force = 400 N (which is the downward force applied against the surface).

So, μ = F/N

= 300 N/400 N

= 3/4

= 0.75

So, the  coefficient of static friction μ = 0.75

6 0
3 years ago
A coil 3.85 cm radius, containing 450 turns, is placed in a uniform magnetic field that varies with time according to B=( 1.20×1
Nimfa-mama [501]

Answer:

0.025V + (0.000218V/s³) t³

Explanation:

Parameters given:

Radius of coil, r = 3.85 cm = 0.0385 m

Number of turns, N = 450

Magnetic field, B = ( 1.20×10^(−2) T/s )t + (2.60×10^(−5) T/s4 )t^4.

The magnitude of Induced EMF is given as:

E = N * A * dB/dt

Where A is the area of the coil

First, we differentiate the magnetic field with respect to time:

dB/dt = 0.012 + 0.000104t³

Therefore, EMF will be:

E = 450 * 3.142 * (0.012 + 0.000104t³)

E = 2.096(0.012 + 0.000104t³)

E = 0.025V + (0.000218V/s³)t³

6 0
3 years ago
Read 2 more answers
What is the value of the initial horizontal velocity?
Dima020 [189]

Initial Velocity is the velocity at time interval t = 0 and it is represented by u. It is the velocity at which the motion starts.

<h2>I hope this helps...</h2><h2>Good day :)</h2>
4 0
3 years ago
A 14000N car traveling at 25m/s rounds a curve of radius 200m. Find the following: a. The centripetal acceleration of the car.
tamaranim1 [39]

Answer:

Explanation:

Given

Weight of car W=14,000\ N

mass of car m=\frac{14,000}{9.8}=1428.57\ N

velocity of car v=25\ m/s

radius r=200\ m

(a)Centripetal acceleration is given by

a_c=\frac{v^2}{r}

a_c=\frac{25^2}{200}

a_c=3.125\ m

(b)Force that provide centripetal acceleration

F=F_c=\frac{mv^2}{r}

F=\frac{1428.57\times 25^2}{200}

F=4464.285\ N

(c)Friction force between car and tires is given by

=\mu N

where \mu=coefficient of static friction

N=normal reaction

Centripetal force will balance the friction force

F_c=F_r

4464.285=\mu \times 1428.57\times 9.8

\mu =0.318

6 0
3 years ago
Read 2 more answers
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