The distance between the object to be viewed and the eyepiece of a compound microscope is 25.0 cm. The focal length of its objec
1 answer:
Answer:
The magnitude of the total magnification of the microscope is 1201.9.
Explanation:
Given that,
Object distance = 25.0 cm
Focal length of its objective lens = 0.200 cm
Focal length of eyepiece = 2.60 cm
We need to calculate the total magnification of the microscope
Using formula for microscope
Where, L = object distance
=Focal length of its objective lens
=Focal length of eyepiece
Put the value into the formula
The magnitude of the total magnification of the microscope
Hence, The magnitude of the total magnification of the microscope is 1201.9.
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Answer:
k = 52.2 N / m
Explanation:
For this exercise we are going to use the conservation of mechanical energy.
Starting point. When it is 30 m high
Em₀ = K + U = ½ m v² + m g h
Final point. Right when you hit the water
= K_{e} = ½ k x²
in this case the distance the bungee is stretched is 30 m
x = h
as they indicate that there are no losses, energy is conserved
Em₀ = Em_{f}
½ m v² + m g h = ½ k h²
k =
let's calculate
k =
k = 52.2 N / m
Answer:
Part A:
Part B:
Explanation:
<u> Part A:</u>
- Potential energy of charge at the given point,
- Charge,
The potential energy at a point due to a charge is defined as
.
<em>where</em>,
V = electric potential at that point.
Therefore,
<u>Part B:</u>
Now, if the charge at that point is replaced with , then the electric potential energy at that point is given by
The vector which shows the velocity of the yo-yo at this moment is A and is denoted as option A.
<h3>What is Velocity?</h3>This is referred to the rate of change of distance with time and the unit is metre per seconds.
A shows the direction of motion is same as the direction of velocity and is the tangent at that particular point hence why it was chosen as the most appropriate choice.
Read more about Velocity here brainly.com/question/6504879
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