3.87 i think but if its not correct then let me know.
Answer:
the power used by the person is 10 W.
Explanation:
Given;
weight lifted, W = 50 N
distance through which the weight was lifted, d = 2 m
time of motion, t = 10 s
The power used by the person is calculated as;

Therefore, the power used by the person is 10 W.
The radius of each jawbreaker is approximately 0.68 cm.
<h3>Volume of a sphere;</h3>
where
r = radius
Therefore,
23 g = 32.3 cm³
0.94 g = ?
cross multiply
volume of a single jawbreaker = 32.3 × 0.94 / 23 = 30.362 / 23 = 1.32 cm³
Therefore,
volume of each jawbreaker = 4 /3 πr³
1.32 = 4 / 3 × 3.14 × r³
r³ = 1.32 /4.18666666667
r³ = 0.31533683707
r = ∛0.31533683707
r = 0.680651651 = 0.68
Therefore, the radius of each jawbreaker is approximately 0.68 cm.
learn more on radius here: brainly.com/question/19172427
Answer:
c. I-O psychology.
Explanation:
According to my research on the different types of psychology fields, I can say that based on the information provided within the question he should consider studying I-O psychology. This is Industrial-Organizational Psychology and focuses on using psychology principles to solve problems in the workplace as well as improving workplace environments. Which is what Stefan would be interested in.
I hope this answered your question. If you have any more questions feel free to ask away at Brainly.
Answer:
In a nutshell, units of A and B are
and
, respectively.
Explanation:
From Dimensional Analysis we understand that
and
have length units (
) and
have time units (
). Then, we get that:
(Eq. 1)
(Eq. 2)
Now we finally clear each constant:
![A = \frac{[l]}{[l]^{3}}](https://tex.z-dn.net/?f=A%20%3D%20%5Cfrac%7B%5Bl%5D%7D%7B%5Bl%5D%5E%7B3%7D%7D)
![A = \frac{1}{[l]^{2}}](https://tex.z-dn.net/?f=A%20%3D%20%5Cfrac%7B1%7D%7B%5Bl%5D%5E%7B2%7D%7D)
![B = \frac{[l]}{[t]}](https://tex.z-dn.net/?f=B%20%3D%20%5Cfrac%7B%5Bl%5D%7D%7B%5Bt%5D%7D)
In a nutshell, units of A and B are
and
, respectively.