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Virty [35]
3 years ago
5

You are working in a shoe test laboratory measuring the coefficients of friction for running shoes on a variety of surfaces. The

shoes are pushed against the surface with a downward force of 400 N, and a sample of the surface material is then pulled out from under the shoe by a machine. The machine pulls with a force of 300 N before the material begins to slide. When the material is sliding, the machine only has to pull with a force of 200 N to keep the material moving. What is the coefficient of static friction between the shoe and the material
Physics
1 answer:
AnnZ [28]3 years ago
6 0

Answer:

0.75

Explanation:

Since the static frictional force is the maximum force applied just before sliding, our frictional force, F is 300 N.

Since F = μN where μ = coefficient of static friction and N = normal force = 400 N (which is the downward force applied against the surface).

So, μ = F/N

= 300 N/400 N

= 3/4

= 0.75

So, the  coefficient of static friction μ = 0.75

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Please help step by step 15 points
BartSMP [9]

3.87 i think but if its not correct then let me know.



3 0
3 years ago
How much power is used if an athlete lifts a 50N weight up 2 meters in 10 seconds?
Tcecarenko [31]

Answer:

the power used by the person is 10 W.

Explanation:

Given;

weight lifted, W = 50 N

distance through which the weight was lifted, d = 2 m

time of motion, t = 10 s

The power used by the person is calculated as;

P= FV\\\\P = F \ \times \ \frac{d}{t} \\\\P = 50 \ \times \ \frac{2}{10} \\\\P = 10 \ W

Therefore, the power used by the person is 10 W.

3 0
3 years ago
A box of spherical jawbreaker candies is 23 g and its volume is 32.3 cm3. If the average mass of a single jawbreaker is 0.94 g,
Alex777 [14]

The radius of each jawbreaker is approximately 0.68 cm.

<h3>Volume of a sphere;</h3>
  • v = 4 /3 πr³

where

r = radius

Therefore,

23 g  = 32.3 cm³

0.94 g  = ?

cross multiply

volume of a single jawbreaker = 32.3 × 0.94 / 23 = 30.362 / 23 = 1.32 cm³

Therefore,

volume of each jawbreaker = 4 /3 πr³

1.32 = 4 / 3 × 3.14 × r³

r³ = 1.32 /4.18666666667

r³ = 0.31533683707

r = ∛0.31533683707

r = 0.680651651 = 0.68

Therefore, the radius of each jawbreaker is approximately 0.68 cm.

learn more on radius here: brainly.com/question/19172427

5 0
3 years ago
Stefan had a terrible work experience when cooking at a local diner while in high school. That experience led him to want to stu
sergejj [24]

Answer:

c. I-O psychology.

Explanation:

According to my research on the different types of psychology fields, I can say that based on the information provided within the question he should consider studying I-O psychology. This is Industrial-Organizational Psychology and focuses on using psychology principles to solve problems in the workplace as well as improving workplace environments. Which is what Stefan would be interested in.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

8 0
3 years ago
A particle moves along a path described by y=Ax^3 ​​ and x = Bt, where tt is time. What are the units of A and B?
Sergeu [11.5K]

Answer:

In a nutshell, units of A and B are \frac{1}{[l]^{2}} and \frac{[l]}{[t]}, respectively.

Explanation:

From Dimensional Analysis we understand that x and y have length units ([l]) and t have time units ([t]). Then, we get that:

[l] = A\cdot [l]^{3} (Eq. 1)

[l] = B\cdot [t] (Eq. 2)

Now we finally clear each constant:

A = \frac{[l]}{[l]^{3}}

A = \frac{1}{[l]^{2}}

B = \frac{[l]}{[t]}

In a nutshell, units of A and B are \frac{1}{[l]^{2}} and \frac{[l]}{[t]}, respectively.

4 0
4 years ago
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