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Gnom [1K]
2 years ago
7

Help asap please need answer

Mathematics
2 answers:
Helga [31]2 years ago
4 0

Answer:

is this on edulastic? if you have the option check answer put 12 and let me know if it was right please.

mr_godi [17]2 years ago
4 0

Answer:

about 21.9 ft²

Step-by-step explanation:

area of a half circle = \frac{\pi r ^{2} }{2}

so \frac{\pi 3^{2} }{2} = 14.13716694 ft²

are of a square is bh\\

so 6 x 6 = 36 ft²

so the area of the figure would equal the area of the square minus the area of the half-circle

36 ft² - 14.13716694 ft² = 21.86283306 ft² ≈ 21.9 ft²

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<img src="https://tex.z-dn.net/?f=%5Csqrt%281-2%29%2B%5Csqrt%281%2B2%29%5C%5C" id="TexFormula1" title="\sqrt(1-2)+\sqrt(1+2)\\"
Kipish [7]
1.4 or square root of 2
8 0
2 years ago
A total of 504tickets were sold for the school play. They were either adult tickets or student tickets. There were 54more studen
LuckyWell [14K]

Answer:

225 adult tickets

Step-by-step explanation:

S: no. of students

A: no. of adults

S = A + 54

S + A = 504

A + A + 54 = 504

2A = 450

A = 225

S = 225 + 54

S = 279

3 0
3 years ago
While researching the cost of school lunches per week across the state, you use a sample size of 45 weekly lunch prices. The sta
Drupady [299]

We assume the lunch prices we observe are drawn from a normal distribution with true mean \mu and standard deviation 0.68 in dollars.


We average n=45 samples to get \bar{x}.


The standard deviation of the average (an experiment where we collect 45 samples and average them) is the square root of n times smaller than than the standard deviation of the individual samples. We'll write


\sigma = 0.68 / \sqrt{45} = 0.101


Our goal is to come up with a confidence interval (a,b) that we can be 90% sure contains \mu.


Our interval takes the form of ( \bar{x} - z \sigma, \bar{x} + z \sigma ) as \bar{x} is our best guess at the middle of the interval. We have to find the z that gives us 90% of the area of the bell in the "middle".


Since we're given the standard deviation of the true distribution we don't need a t distribution or anything like that. n=45 is big enough (more than 30 or so) that we can substitute the normal distribution for the t distribution anyway.


Usually the questioner is nice enough to ask for a 95% confidence interval, which by the 68-95-99.7 rule is plus or minus two sigma. Here it's a bit less; we have to look it up.


With the right table or computer we find z that corresponds to a probability p=.90 the integral of the unit normal from -z to z. Unfortunately these tables come in various flavors and we have to convert the probability to suit. Sometimes that's a one sided probability from zero to z. That would be an area aka probability of 0.45 from 0 to z (the "body") or a probability of 0.05 from z to infinity (the "tail"). Often the table is the integral of the bell from -infinity to positive z, so we'd have to find p=0.95 in that table. We know that the answer would be z=2 if our original p had been 95% so we expect a number a bit less than 2, a smaller number of standard deviations to include a bit less of the probability.


We find z=1.65 in the typical table has p=.95 from -infinity to z. So our 90% confidence interval is


( \bar{x} - 1.65 (.101),  \bar{x} + 1.65 (.101) )


in other words a margin of error of


\pm 1.65(.101) = \pm 0.167 dollars


That's around plus or minus 17 cents.




3 0
3 years ago
Read 2 more answers
What’s the answer to this question
creativ13 [48]

Answer:

j

Step-by-step explanation:

4 0
3 years ago
10=3x+1-4<br> How do I solve this problem?
scZoUnD [109]
Your answer issssss 0 !!
5 0
3 years ago
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